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Alborosie
3 years ago
10

Use graph to answer question

Mathematics
1 answer:
slamgirl [31]3 years ago
5 0

Answer:

cos(θ) = 3/5

Step-by-step explanation:

We can think of this situation as a triangle rectangle (you can see it in the image below).

Here, we have a triangle rectangle with an angle θ, such that the adjacent cathetus to θ is 3 units long, and the cathetus opposite to θ is 4 units long.

Here we want to find cos(θ).

You should remember:

cos(θ) = (adjacent cathetus)/(hypotenuse)

We already know that the adjacent cathetus is equal to 3.

And for the hypotenuse, we can use the Pythagorean's theorem, which says that the sum of the squares of the cathetus is equal to the square of the hypotenuse, this is:

3^2 + 4^2 = H^2

We can solve this for H, to get:

H = √( 3^2 + 4^2) = √(9 + 16) = √25 = 5

The hypotenuse is 5 units long.

Then we have:

cos(θ) = (adjacent cathetus)/(hypotenuse)

cos(θ) = 3/5

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90/48<br><br> show how you got the answer
DiKsa [7]

Answer: Basically divide both number.

Step-by-step explanation:

Go to App sotr if u got iPhone or if u got android go to play store and download the app called PHOTOMATH and when u scan the answer it's gonna show the steps and the answer.

5 0
3 years ago
Simplify the equation
gtnhenbr [62]

Answer:

option c is the correct.

Step-by-step explanation:

\frac{2x^4*6x^2}{3x^2}

by using the laws of exponent

a^m×a^n=a^m+n

12x^4+2/3x²

\frac{12x^4}{3x^3}

4x^4-3

4x³

6 0
3 years ago
Read 2 more answers
Remove the parentheses from the expression (–2) – (–3). A. 2 – 3 B. –2 + 3 C. 2 + 3 D. –2 – 3
lukranit [14]

Answer:

B.

Step-by-step explanation:

The negative of a negative is a positive, so B is your choice.  Think of it anothe way, if it helps.  Imagine that the expression is this:

(-2) + (-1)(-3) since every subtraction problem can be rewritten as an addition problem.

We would first, by orders of operation, multiply the -1 and the -3 getting 3.  Then the problem would simplify down to -2 + 3

Just another idea to ponder...

5 0
2 years ago
A company that explores for oil in the ocean is considering two new sites, A and B. The exploration will take the entire year. T
Lelu [443]

Answer:

Step-by-step explanation:

Hello!

There are two sites A and B,

Be the events A: finding oil in site Awith probability P(A)= 0.6

and B: finding oil in B with probability P(B)= 0.84

A and B are independent (there cannot be found oil of A in B and vice versa)

Remember, two events are independent when the occurrence of one of them doesn't modify the probability of occurrence of the other one in two repetitions of the experiment.

1) Find the probability that oil is found at both sites (round your answer to 2 decimal places)

If there is oil in both sites then event A and B are observed, symbolically:

P(A∩B)

Since both events are independent, the probability of the intersection of both events is equal to the product of each probability so:

P(A∩B)= P(A)*P(B)= 0.6*0.84= 0.504

2) Find the probability that oil is found at only one of the sites (round your answer to 2 decimal places)

In this case, you have two situations in which the statement can occur:

> "finding oil in A" and "not finding oil in B"

-or-

> "not finding oil in A" and "finding oil in B"

Be A' the complementary event of A, i.e. "not finding oil in region A", with probability P(A')= 1 - P(A)= 1 - 0.6= 0.4

And B' the complementary event of B, i.e. "not finding oil in region B", with probability P(B')= 1 - P(B)= 1 - 0.84= 0.16.

You can symbolize these two possible occurrences as:

Remember that "and" indicated intersection between two events, symbolized ∩, and "or" indicates the union between two events, symbolized ∪.

P((A∩B')∪(A'∩B))= P(A∩B') + P(A'∩B)= [P(A)*P(B')]+[P(A')*P(B)]= (0.6*0.16)+(0.4*0.84)= 0.432

I hope it helps!

7 0
2 years ago
number 3 says,"If u and v are the measures of complementary angles such that sin u =2/5 and tan v =(square root of 21) 21/2, lab
vodomira [7]

Answer and Explanation:

Using trig ratios, we can express the given values of sin u and tan v as shown below

\begin{gathered} \sin u=\frac{opposite\text{ of angle u}}{\text{hypotenuse}}=\frac{2}{5} \\ \tan v=\frac{opposite\text{ of angle v}}{\text{hypotenuse}}=\sqrt[]{21} \end{gathered}

So we can go ahead and label the sides of the triangle as shown below;

We can find the value of u as shown below;

\begin{gathered} \sin u=\frac{2}{5} \\ u=\sin ^{-1}(\frac{2}{5}) \\ u=23.6^{\circ} \end{gathered}

We can find v as shown below;

\begin{gathered} u+v+90=180\text{   (sum of angles in a triangle)} \\ v+23.6+90=180 \\ v=180-113.6 \\ v=66.4^{\circ} \end{gathered}

5 0
1 year ago
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