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Ksenya-84 [330]
3 years ago
9

Let the vector \mathbf{v}v have an initial point at (1, -2)(1,−2) and a terminal point at (0, 0)(0,0). Plot the vector \mathbf{v

}v and afterwards follow the guided steps to analyze the vector.
Mathematics
1 answer:
ASHA 777 [7]3 years ago
4 0

Given that the initial point of the vector is (1,-2) and the termination point of the vector is (0,0).

So, the tail of the vector is at point (1,-2) and the head of the vector is at (0,0). The vector, \vec{v}, has been shown in the figure.

The magnitude of the vector:

|\vec{v}|=\sqrt{(1-0)^2+(-2-0)^2}=\sqrt{1+4}=\sqrt{5}

The direction of a vector is the angle made by a vector with the positive direction of the x-axis.

From the figure, \theta = 180 \degree\tan ^{-1} \left|\frac {0-(-2)}{0-1}\right|

\theta = 180 ^{\circ} - \tan^{-1}(2) = 180 ^{\circ} - 63.43^{\circ}

\theta =116.57 ^{\circ}

Hence, the required vector having a magnitude \sqrt {5} and direction 116.57 ^{\circ} has been shown in the figure.

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Answer: Area (upper bound) = 4527.7056 cm²

               Perimeter (lower bound) = 278 cm

<u>Step-by-step explanation:</u>

The length and width of the rectangle have been ROUNDED to the nearest tenth. Let's calculate what their actual measurements could be:

LENGTH: rounded to 87.3,  actual is between 87.25 and 87.34

<em>87.25 is the lowest number it could be that would round it UP to 87.3</em>

<em>87.34 is the highest number it could be that would round DOWN to 87.3</em>

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<em>51.75 is the lowest number it could be that would round it UP to 51.8</em>

<em>51.84 is the highest number it could be that would round DOWN to 51.8</em>

To find the Area of the upper bound, multiply the highest possible length and the highest possible width:

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