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joja [24]
3 years ago
12

YOOOOOOOo i need some help with the problem in the photo below 0-0

Mathematics
2 answers:
irinina [24]3 years ago
6 0

Answer: 4

Step-by-step explanation:

2+2 =4

I.E  If I have 2 apples and my friend has 2 apples, we would have 4 in total.

Mazyrski [523]3 years ago
6 0

Answer:

I think its 4 but I mean that's a hard one

Step-by-step explanation:

goldfish plus goldfish

=2 goldfish

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What is 9 3/4 - 6:00
Pavlova-9 [17]
3/4 is 45 minutes, cause a quarter of an hour is 15 minutes. 6-9 = -3 so you basically do Noon subtracted by another 3 hours which is 9 am, then subtract those 45 minutes

6pm - 6 hours = 12pm
(Noon) 12pm - 3 hours= 9am
then 45 minutes
9am - 45 minutes
8:15AM
3 0
3 years ago
Completely simplify the rational expression LaTeX: \frac{7x}{3y} + \frac{12x}{9y}
irina [24]

Answer:

\frac{11x}{3y}

Step-by-step explanation:

\frac{7x}{3y} + \frac{12x}{9y}

To add the two fractions, you need a common denominator.  In this case, the lowest common denominator (LCD) is 9y.  That's because 9y is divisible by both 3y and 9y.

The first fraction must be changed so that its denominator is 9y.  Do this by multiplying both numerator and denominator by 3.

\frac{7x}{3y}\cdot\frac{3}{3}+\frac{21x}{9y}=\frac{21x}{9y}+\frac{12x}{9y}\\=\frac{21x+12x}{9y}\\=\frac{33x}{9y}

Finally, this answer can be simplified ("reduced") by dividing both numerator and denominator by 3, their greatest common factor.

3 0
3 years ago
Nth term formula? maths quickly
vladimir1956 [14]

\text{Nth term of an arithmetic series} = a +(n-1)d \\\\\text{Nth term of an geometric series}= ar^{n-1}\\\\\text{where,}\\\\\text{a = first term.}\\\\\text{d = common difference.}\\\\\text{r = common ratio.}

6 0
2 years ago
Use compatible numbers to estimate 248.26+159.72
antoniya [11.8K]
250.00 + 160.00=410.00
or
249.00 + 160.00= 409.00
8 0
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Read 3 more answers
If x>2, then x^2-x-6/x^2-4=
Viefleur [7K]
Consider the expression \frac{x^{2} -x-6}{ x^{2} -4}

To factorize the expression in the denominator we use difference of squares: x^{2} -4=x^{2} - 2^{2} =(x-2)(x+2)

To factorize x^{2} -x-6 we use the following method:

x^{2} -x-6=(x-a)(x-b)

where a, b are 2 numbers such that a+b= -1, the coefficient of x,

and a*b= -6, the constant.

such 2 numbers can be easily checked to be -3 and 2

(-3*2=6, -3+2=-1)

So x^{2} -x-6=(x-a)(x-b)=(x+3)(x-2)


 \frac{x^{2} -x-6}{ x^{2} -4}= \frac{(x+3)(x-2)}{(x-2)(x+2)}= \frac{x+3}{x+2}


\frac{x+3}{x+2}= \frac{x+2+1}{x+2}= \frac{x+2}{x+2}+ \frac{1}{x+2}=1+ \frac{1}{x+2}

for x>2

\frac{1}{x+2}\ \textless \  \frac{1}{2+2}= \frac{1}{4}

thus

for x>2, 

1+ \frac{1}{x+2}\ \textless \ 1+ \frac{1}{4}= \frac{5}{4}


Answer: 

for x>2

\frac{x^{2} -x-6}{ x^{2} -4} =  \frac{x+3}{x+2} \ \textless \  \frac{5}{4}, (but the expression is never 0)
8 0
4 years ago
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