<span>f(x) = x2 + 4 g(x) = x2 − x + 5
</span>f(x) · g(x) = (fg)(x) = (x^2 + 4)(<span> x^2 − x + 5)
</span>f(x) · g(x) = (fg)(x) = x^4 - x^3 + 5x^2 + 4x^2 - 4x + 20
f(x) · g(x) = (fg)(x) = x^4 - x^3 + 9x^2 - 4x + 20
answer
f(x) · g(x) = (fg)(x) =
x^4 - x^3 + 9x^2 - 4x + 20
Answer:
C
Step-by-step explanation:
You have to multiply the number of dollars times the conversion ratio is used in this way.
If you use the nearest hundredth approximation of the conversion ratio you have to use 1.35 instead the real exchange ratio of 1.35261
So, if they change Eu 1 will receive $ 1.35 instead of $ 1.35261.
If they change Eu 10 will receive 10 × 1.35 = $ 13.5, instead of $13.5261
If they change Eu 100 will receive 100 × 1.35 = $ 135, instead of $135.5261
If they change Eu 1,000 will receive 1000 × 1.35 = $ 1350, instead of $ 1352.61
So, you see the lose is $ 2.61 per every 1000 Euros they change.
I hope this helps you
f(x) =sinx
f^-1(x)=arcsinx
arcsinx is inverse of sinx function
Answer:
he only got 93.333333333333% of what he thought he was going to get
Step-by-step explanation:
