Answer: Transitive property of congruence
We have this table
![\begin{array}{|c|c|c|c|c|}\cline{1-5}\text{outcome}&A&B&C&D\\ \cline{1-5}\text{frequency}&20&11&14&30\\ \cline{1-5} \end{array} \\](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7B%7Cc%7Cc%7Cc%7Cc%7Cc%7C%7D%5Ccline%7B1-5%7D%5Ctext%7Boutcome%7D%26A%26B%26C%26D%5C%5C%20%5Ccline%7B1-5%7D%5Ctext%7Bfrequency%7D%2620%2611%2614%2630%5C%5C%20%5Ccline%7B1-5%7D%20%5Cend%7Barray%7D%20%5C%5C)
The values in the bottom row add to 20+11+14+30 = 75, so that matches up with the fact that the spinner was spun 75 times. Of those 75 spins, 11+14 = 25 landed on either B or C.
So 25/75 = 0.33 is the approximate experimental probability of landing on B or C.
<h3>Answer: Choice A) 0.33</h3>
Answer:
take 1 plus 3 and divide by 6 :) then say WARFTYGVDHBJNKM<L>
Step-by-step explanation:
9. f(x) = -x + 5 [-3, 2]
f(x) = -x + 5 {-3 ≤ x ≤ 2}
10. f(x) = 1.5x + 1 {x| x > 2}
f(x) = 1.5x + 1 (2, ∞)
Answer:
y=/x+1/ + 5
Step-by-step explanation: