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3 years ago

OI PLS ANSWER QUICK PLEASE I WILL GIVE BRAINLIEST

Mathematics

2 answers:

harkovskaia [24]3 years ago

8 0

Answer:

The answer is 4

cause cancel out the 9 and divide 8and 2

mixas84 [53]3 years ago

3 0

Answer:

16/81

Step-by-step explanation:

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PLEASE NEED ANSWER FAST

ahrayia [7]

c or d for sure hope this helps

5 0

2 years ago

Identify the angle of depression.<br> 3<br> 6<br> 4<br> 5

dsp73

Answer: Angle 4

Step-by-step explanation:

The angle of depression is formed by the line of sight and the horizontal line tangent to the top of the observer.

5 0

2 years ago

Write the expression 6a in words

alekssr [168]

An apple has an unknown cost of a

I decide to buy 6 apples.

I will have to pay 6a for the apples

3 0

3 years ago

Can you show work for 8.01/0.9

Gnoma [55]

Answer:8.01/0.9=8.9

Step-by-step explanation:

3 0

3 years ago

Integrate the following

enot [183]

I suppose you mean to have the entire numerator under the square root?

$\displaystyle\int_2^4\frac{\sqrt{x^2-4}}{x^2}\,\mathrm dx$

We can use a trigonometric substitution to start:

$x=2\sec t\implies\mathrm dx=2\sec t\tan t\,\mathrm dt$

Then for $x=2$ , $t=\sec^{-1}1=0$ ; for $x=4$ , $t=\sec^{-1}2=\frac\pi3$ . So the integral is equivalent to

$\displaystyle\int_0^{\pi/3}\frac{\sqrt{(2\sec t)^2-4}}{(2\sec t)^2}(2\sec t\tan t)\,\mathrm dt=\int_0^{\pi/3}\frac{\tan^2t}{\sec t}\,\mathrm dt$

We can write

$\dfrac{\tan^2t}{\sec t}=\dfrac{\frac{\sin^2t}{\cos^2t}}{\frac1{\cos t}}=\dfrac{\sin^2t}{\cos t}=\dfrac{1-\cos^2t}{\cos t}=\sec t-\cos t$

so the integral becomes

$\displaystyle\int_0^{\pi/3}(\sec t-\cos t)\,\mathrm dt=\boxed{\ln(2+\sqrt3)-\frac{\sqrt3}2}$

7 0

3 years ago