In rhombus FGHJ, m∠1=37°. What is m∠2?
2 answers:
Answer:
m∠2 = 53°
Step-by-step explanation:
We will use two properties of a rhombus to solve this problem.
1). Opposite angles of a rhombus are equal.
2). Diagonals bisect the angles.
Since ∠JFG and ∠JHG are the opposite angles of the rhombus,
m∠JFG = m∠JHG
Since, diagonal FH bisect ∠JHG,
m∠FHJ = m∠GHF = m∠JFH = m∠GFH = 37°
In triangle JFH,
m∠FHJ + m∠JFH + m∠HJF = 180°
37° + 37° + m∠HJF = 180°
m∠HJF = 180 - 74
= 106°
Since, diagonal GJ bisects angle HJF,
m∠FJG = = 53°
Therefore, m∠2 = 53°.
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Answer:
Length of the shadow of the pole is 6.93 metres
Step-by-step explanation:
Given:
Height of the pole = 4 m
The angle sun makes with the horizontal = 30 degrees
To Find:
Length of the shadow of the pole = ?
Solution:
The tangent ratio is the value received when the length of the side opposite of angle theta is divided by the length of the side adjacent to angle theta
Let x be the length of the shadow
According to the tangent ratio
On substituting the values,
x = 6.93 m
