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maxonik [38]
3 years ago
11

Write the equation to find the missing side of this triangle.

Mathematics
2 answers:
Yuki888 [10]3 years ago
7 0

Answer: Pythagorean theorem which a² + b² = c².

Step-by-step explanation:  This is showing me with the information you have given me a pythagorean triple.

Exp: This is a common pythagorean triple (6,8,10)

6²+8²=10².

10 is the hypotenuse which is the longest and is across the 90 angle.

6²=36 and 8²=64 which if you add both numbers equal 100. 10² is 100. You know it is a common pythagorean since both sides have the same number.

Vlad1618 [11]3 years ago
3 0

Answer:

x^2+8^2=10^2

Step-by-step explanation:

Use Pythagorean theorem, which states that for legs of a right triangle a and b, and the hypotenuse of that triangle c,

a^2+b^2=c^2

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ludmilkaskok [199]
The common ratio is -5, note that each value is the previous value multiplied by -5.
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3 years ago
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Ne4ueva [31]

Answer: its b

Step-by-step explanation:

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8 0
3 years ago
Find the remaining trigonometric ratios of θ if csc(θ) = -6 and cos(θ) is positive
VikaD [51]
Now, the cosecant of θ is -6, or namely -6/1.

however, the cosecant is really the hypotenuse/opposite, but the hypotenuse is never negative, since is just a distance unit from the center of the circle, so in the fraction -6/1, the negative must be the 1, or 6/-1 then.

we know the cosine is positive, and we know the opposite side is -1, or negative, the only happens in the IV quadrant, so θ is in the IV quadrant, now

\bf csc(\theta)=-6\implies csc(\theta)=\cfrac{\stackrel{hypotenuse}{6}}{\stackrel{opposite}{-1}}\impliedby \textit{let's find the \underline{adjacent side}}
\\\\\\
\textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a
\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
\pm\sqrt{6^2-(-1)^2}=a\implies \pm\sqrt{35}=a\implies \stackrel{IV~quadrant}{+\sqrt{35}=a}

recall that 

\bf sin(\theta)=\cfrac{opposite}{hypotenuse}
\qquad\qquad 
cos(\theta)=\cfrac{adjacent}{hypotenuse}
\\\\\\
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}
\qquad \qquad 
% cotangent
cot(\theta)=\cfrac{adjacent}{opposite}
\\\\\\
% cosecant
csc(\theta)=\cfrac{hypotenuse}{opposite}
\qquad \qquad 
% secant
sec(\theta)=\cfrac{hypotenuse}{adjacent}

therefore, let's just plug that on the remaining ones,

\bf sin(\theta)=\cfrac{-1}{6}
\qquad\qquad 
cos(\theta)=\cfrac{\sqrt{35}}{6}
\\\\\\
% tangent
tan(\theta)=\cfrac{-1}{\sqrt{35}}
\qquad \qquad 
% cotangent
cot(\theta)=\cfrac{\sqrt{35}}{1}
\\\\\\
sec(\theta)=\cfrac{6}{\sqrt{35}}

now, let's rationalize the denominator on tangent and secant,

\bf tan(\theta)=\cfrac{-1}{\sqrt{35}}\implies \cfrac{-1}{\sqrt{35}}\cdot \cfrac{\sqrt{35}}{\sqrt{35}}\implies \cfrac{-\sqrt{35}}{(\sqrt{35})^2}\implies -\cfrac{\sqrt{35}}{35}
\\\\\\
sec(\theta)=\cfrac{6}{\sqrt{35}}\implies \cfrac{6}{\sqrt{35}}\cdot \cfrac{\sqrt{35}}{\sqrt{35}}\implies \cfrac{6\sqrt{35}}{(\sqrt{35})^2}\implies \cfrac{6\sqrt{35}}{35}
3 0
3 years ago
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klasskru [66]

Answer:

figure it out

Step-by-step explanation:

Pick two point and do 10-0 over -5+3 and you get your slope

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Which of the following statements is true?
Ivahew [28]

The correct answer is C. A scalene triangle can be a right triangle.


This is because a scalene triangle is a triangle where all of the sides and angles are different from one another. This automatically tells us that options A and D are incorrect, because equiangular triangles have all 3 angles equivalent and if two sides were of equal length in the triangle, then it would not be scalene.


This leaves us with options B and C. An obtuse triangle simply has one angle with a measure greater than 90 degrees, and a right triangle is a triangle with a right angle (an angle that measures exactly 90 degrees). Scalene triangles can be both obtuse and right, as long as the side lengths and angles are not equal to one another. This makes option B incorrect, and option C the only correct option out of the four.


Your answer is option C.


Hope this helps!

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3 years ago
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