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3 years ago

I need help its due today

Mathematics

2 answers:

kenny6666 [7]3 years ago

7 0

Answer:

8(8d+1)

Step-by-step explanation:

Jobisdone [24]3 years ago

4 0

Answer:

64d+8

64/8 d + 8/8

=8(8d+1)

Step-by-step explanation:

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PIT_PIT [208]

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3 years ago

Four-thirds times the sum of a number and 8 is 24.what is the number

ZanzabumX [31]

Answer:

x=10

Step-by-step explanation:

(4/3) * ( x + 8) = 24

24-8 is 8

18-8 is 10

That gets you x=10.

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3 years ago

Six more than five times a number (x) is at least twenty-one

I am Lyosha [343]

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3 years ago

What expression is equivalent to ^3 square root of 2y^3 times 7 square root of 18y

Mumz [18]

Answer:

$\sqrt[3]{2y^3} * 7\sqrt{18y} = 21(y^{\frac{3}{2}})(2^{\frac{5}{6}})$

Step-by-step explanation:

The question is poorly formatted.

Given

$\sqrt[3]{2y^3} * 7\sqrt{18y}$

Required

Derive an equivalent expression

$\sqrt[3]{2y^3} * 7\sqrt{18y}$

Express 18 as 9 * 2

$\sqrt[3]{2y^3} * 7\sqrt{9 * 2y}$

Split the expression as follows:

$\sqrt[3]{2y^3} * 7\sqrt{9} * \sqrt{2y}$

Take positive square root of 9

$\sqrt[3]{2y^3} * 7*3 * \sqrt{2y}$

$\sqrt[3]{2y^3} * 21 * \sqrt{2y}$

$21*\sqrt[3]{2y^3} * \sqrt{2y}$

The cube root can be rewritten to give:

$21*\sqrt[3]{2}*\sqrt[3]{y^3} * \sqrt{2y}$

$\sqrt[3]{y^3} = y^{3*\frac{1}{3}} = y$

So, we have:

$21*\sqrt[3]{2} * y * \sqrt{2y}$

Rewrite as:

$21y *\sqrt[3]{2} * \sqrt{2y}$

Split $\sqrt{2y$

$21y *\sqrt[3]{2} * \sqrt{2} * \sqrt{y}$

Collect Like Terms

$21y*\sqrt{y} *\sqrt[3]{2} * \sqrt{2}$

Represent in index form

$21y*y^{\frac{1}{2}} *2^\frac{1}{3} *2^\frac{1}{2}$

Apply law of indices

$21*y^{1+\frac{1}{2}} *2^{\frac{1}{3} +\frac{1}{2} }$

$21*y^{\frac{2+1}{2}} *2^{\frac{2+3}{6}}$

$21*y^{\frac{3}{2}} *2^{\frac{5}{6}}$

$21(y^{\frac{3}{2}})(2^{\frac{5}{6}})$

Hence:

$\sqrt[3]{2y^3} * 7\sqrt{18y} = 21(y^{\frac{3}{2}})(2^{\frac{5}{6}})$

6 0

3 years ago

What is the multiple zero and multiplicity of f(x) = x3+2x2+2

icang [17]

Answer:

I assume you mean...

"What are the roots of the polynomial and their multiplicity..."

x3+2x2+x = x(x2+2x+1) = x(x+1)(x+1) or x(x+1)2

The roots are x = 0, multiplicity 1

x = -1, multiplicity 2

7 0

3 years ago