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3 years ago

...............................

Mathematics

1 answer:

valkas [14]3 years ago

3 0

I believe it’s 7/10

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Hhehevdhhbbdbdbdbbshdhd that pink doesn't work

Anarel [89]

Answer:

Step-by-step explanation:

6 0

2 years ago

If each song was 2.5 minutes long, how many minutes of music total did Jen listen to?

Dafna1 [17]

Answer:

Well. it depends on how many songs... so

Step-by-step explanation:

1 x 2.5. 2.5. 2 x 2.5. 3 x 2.5. 7.5. 4 x 2.5. 5 x 2.5. 12.5. 6 x 2.5. 7 x 2.5. 17.5. 8

7 0

4 years ago

Read 2 more answers

Suppose that we have the following sequence :

Jlenok [28]

$a_n=\dfrac12a_{n-1}$
$a_n=\dfrac1{2^2}a_{n-2}$
$a_n=\dfrac1{2^3}a_{n-3}$
$a_n=\cdots=\dfrac1{2^{n-1}}a_1$
$a_n=\dfrac1{2^{n-1}}$

$b_n=b_{n-1}+\dfrac1{2^{n-1}}$
$b_n=b_{n-2}+\dfrac1{2^{n-1}}+\dfrac1{2^{n-2}}$
$b_n=b_{n-3}+\dfrac1{2^{n-1}}+\dfrac1{2^{n-2}}+\dfrac1{2^{n-3}}$
$b_n=\cdots=b_1+\dfrac1{2^{n-1}}+\dfrac1{2^{n-2}}+\cdots+\dfrac12$
$b_n=a_1+\displaystyle\sum_{k=1}^{n-1}\frac1{2^{n-k}}$
$b_n=1+\displaystyle\sum_{k=1}^{n-1}\frac1{2^{n-k}}$
$b_n=\displaystyle\sum_{k=1}^n\frac1{2^{n-k}}$
$b_n=\displaystyle\frac1{2^n}\underbrace{\sum_{k=1}^n2^k}_{S_n}$

$S_n=1+2+2^2+\cdots+2^{n-1}+2^n$
$\implies2S_n=2+2^2+2^3+\cdots+2^n+2^{n+1}$
$\implies S_n-2S_n=-S_n=1-2^{n+1}$
$\implies S_n=2^{n+1}-1$

$b_n=\dfrac{2^{n+1}-1}{2^n}=2-\dfrac1{2^n}$

$\implies b_{50}=2-\dfrac1{2^{50}}\approx1.99999999999999911182158$

$\implies b_{10^6}=2-\dfrac1{2^{10^6}}\approx2.00000000000000000000000$

8 0

3 years ago

10/3 is equal to 3 1/3

Mila [183]

We can see 10/3 is an improper fraction. This can be represented as a mixed number that will have a whole number as well as a fractional part. The quotient of 10 divided by 3 is 3 While the remainder of 10 divided by 3 is 1.

Thus, 10/3 in a mixed fraction is 3 1/3.

3 0

3 years ago

What is −56÷910? −2725 −43 −2527 −34 (Help needed lol)

SOVA2 [1]

Answer:

0.0615384

Step-by-step explanation:

None of the answer choose match my answer

-56/910= 0.0615384

7 0

4 years ago

Read 2 more answers