3 years ago

Como resuelvo esta inecuació 2x + 8 ≥ 20?

Mathematics

1 answer:

stiv31 [10]3 years ago

8 0

Answer:

x≥6

Step-by-step explanation:

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Match the two numbers with their least common multiple (LCM).

timurjin [86]

Answer:

8 and 4: A
8 and 6: C
8 and 10: B

Step-by-step explanation:

8 and 4:

Multiples of 8: 8, 16, 24

Multiples of 4: 4, 8, 12, 16

8 and 6:

Multiples of 8: 8, 16, 24

Multiples of 6: 6, 12, 18, 24

8 and 10:

Multiples of 8: 8, 16, 24, 32, 40

Multiples of 10: 10, 20, 30, 40

4 0

3 years ago

The length of a rectangle is eight centimeters less than twice its width. If the perimeter of

natita [175]

Answer:

width of given rectangle = 6 cm

length of given rectangle = 4 cm

Step-by-step explanation:

Let the breadth be x cm

given that

The length of a rectangle is eight centimeters less than twice its width

length of rectangle in terms of x = 2(breadth ) - 8 = 2x - 8

we know perimeter of rectangle is given = 2(l + b)

thus, perimeter of given rectangle is = 2 ( x + 2x - 8) = 6x - 16

also given perimeter of the rectangle is 20 centimeters

thus,

6x - 16 = 20

6x = 20 + 16 = 36

x = 36/6 = 6

Thus,

width of given rectangle = 6 cm

length of given rectangle = 2*6 - 8 = 4 cm

7 0

3 years ago

Simplify the expression: 2(3n+4)-2(2n+5)

inessss [21]

First use distributive property:
2(3n + 4) - 2(2n + 5)
6n + 8 - 4n - 10
Group like terms:
6n - 4n + 8 - 10
Add like terms:
2n - 2

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Answer:

3/4?

Step-by-step explanation:

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