Answer:
it's J
Step-by-step explanation
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Answer:
yes you can
apart from getting rid of the denominator you can collect like terms
Step-by-step explanation:
d=6-3/5
6=30/5
30/5-3/5
27/5
d=27/5
Suppose the larger pump alone can empty the tank in L hours, and the smaller pump can finish the job in S hours, then each hour the large pump empties 1/L portion of the tank, and the small pump empties 1/S per hour
Working together for three hours, they empty the whole tank, which is 100% of it, so 3/L+3/S=100%=1
Larger pump can empty the tank in 4 hours less than the smaller one, so L=S-4
replace L: 3/(S-4)+3/S=1
Make the denominator the same to solve for:
3S/[S(S-4)] +3(S-4)/[S(S-4)]=1
(3S+3S-12)/[S(S-4)]=1
(3S+3S-12)=[S(S-4)]
S^2-10s+12=0
use the quadratic formula to solve for S
S is about 8.6
The answer is not whole hour.
We have that
the Volume of cone=(1/3)*B*h
B=the area of the base
h= the height of the cone
D=3.5 in-----------------> r=D/2=1.75 in
h=5 in
B=pi*r²---------> 3.14*1.75²=9.616 in²
V=(1/3)*9.616*5=48.08 in³--------> 48 in³
the answer is 48 in³