A quadratic function is given by y = ax^2 + bx + c
c(2) = a(2)^2 + 2b + c = 45
4a + 2b + c = 45 . . . (1)
c(4) = a(4)^2 + 4b + c = 143
16a + 4b + c = 143 . . . (2)
c(10) = a(10)^2 + 10b + c = 869
100a + 10b + c = 869 . . . (3)
Solving (1), (2) and (3) gives a = 9, b = -5, c = 19
Therefore, c(x) = 9x^2 - 5x + 19
c(7) = 9(7)^2 - 5(7) + 19 = 9(49) - 35 + 19 = 441 - 16 = 425
Therefore, it costs $425 to produce 7 calculators.
Answer:
x=924
Step-by-step explanation:
348 + 926 = x + 350
we have two 2-terms additions in both sides of the equation.
348 and 350 are two <em>similar</em> numbers then x and 926 should be really <em>close</em> numbers.
(due to commutative property of additions 348 + 926 = 350 + x)
<em>since 348 has two units less than 350, then 926 must have two units more than x, and <u>x=924</u></em>
(indirect proportionality)
Answer:
4x+3y-10=0
Step-by-step explanation:
first find the gradient of the line that is perpendicular to the line of interest.
y2-y1/x2-x1
3--3/6--6
=3+3/6+6
=9/12
3/4
The gradient of the line of interest is the negative reciprocal of 3/4. Therefore m is -4/3
next, substitute information into
y-y1=m(x-x1)
y-2=-4/3 (x-1)
multiply both sides of equation by 3
3y-6=-4 (x-1)
expand brackets
3y-6=-4x+4
rearrange in general form
4x+3y-10=0
Answer:
25, 36, 49
Step-by-step explanation:
I just listed them down since there aren't many.
1×1=2 (Smaller than 20)
2×2=4 (Smaller than 20)
3×3=9 (Smaller than 20)
4×4=16 (Smaller than 20)
5×5=25
6×6=36
7×7=49
8×8=64 (Bigger than 50)
You start by looking at what number can divide evenly into both 16 and 48. Both numbers are divisible by 16. 16 goes into 16 once and 16 goes into 48 three times. So you divide each term by 16 and your expression should look like this: 16 (p+3)
