Answer:
csc θ =
/6
sec θ =
/7
tan θ = 6/7
Step-by-step explanation:
The first thing to do will be to compute the length of the hypotenuse using the Pythagoras theorem;
6^2 +7^2 = hypotenuse^2
hypotenuse = 
csc θ = 1/sinθ
sinθ = opposite side/hypotenuse
= 6/
csc θ =
/6
sec θ = 1/cosθ
cosθ = adjacent side/hypotenuse
sec θ = hypotenuse/adjacent side
=
/7
tan θ = Opposite side/adjacent side
= 6/7
Answer:
11 inches
Step-by-step explanation:
A rectangle's perimeter can be found using:
p=2l+2w
We know that the perimeter, p, is 58, and the length/height is 18. Therefore, we can substitute those values in
58=2(18)+2w
Multiply 2 and 18
58=36+2w
Since we want to find the width, we need to get w by itself. First, subtract 26 from both sides
58-36=36-36+2w
22=2w
Since w is being multiplied by 2, divide both sides by 2. This will cancel out the 2, and leave w by itself.
22/2=2w/2
11=w
So, the width is 11 inches
Answer:
a) 
b)
deviations
c) 
d) For this case since we have that z>2 we can consider this value as unusual, since is outside of the interval considered usual.
Step-by-step explanation:
Assuming this complete question : "Helen Mirren was 61 when she earned her Oscar-winning Best Actress award. The Oscar-winning Best Actresses have a mean age of 35.8 years and a standard deviation of 11.3 years"
a) What is the difference between Helen Mirren’s age and the mean age?
For this case we can do this:

b) How many standard deviations is that?
We just need to take the difference and divide by the deviation and we got:
deviations
c) Convert Helen Mirren’s age to a z score.
The z score is defined as:

And if we replace the values given we got:

d) If we consider “usual” ages to be those that convert to z scores between –2 and 2, is Helen Mirren’s age usual or unusual?
For this case since we have that z>2 we can consider this value as unusual, since is outside of the interval considered usual.