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algol13
3 years ago
12

Name a pair of parallel lines

Mathematics
1 answer:
trasher [3.6K]3 years ago
3 0
The first one is the correct answer
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Express your answer as a polynomial in standard form.
andrezito [222]
I personally don’t know the answer so i can’t help
4 0
3 years ago
A chemist is conducting an experiment which involves a certain chemical reaction. He begins the experiment with 666 milliliters
Ket [755]

Answer:

8 Minutes

Step-by-step explanation:

since we are trying to find how many minutes have passed we first need to find how much substance was used during the time. we can do that by subtracting the leftover substance from the amount we started with.

666-562 = 104

Now that we know how much substance was used we can then use our conversion rate (13 per minute) and find how many minutes have passed by dividing.

104 / 13 = 8

4 0
3 years ago
Help! open the attachment below!
gregori [183]

Answer:

yes it is

Step-by-step explanation:X=side lenghths 2/3

                                            Y=perimeter 12/18

2 time 6=12 and 3 times 6=18 and it is paraticly telling you

2/6 and 3/6 i beleve i need a lil more info

6 0
3 years ago
Tina and maryann each play tennis. Maryann has won 5 more games than Tina. Is it possible for tina to have won games if the sum
Soloha48 [4]

Answer:

Tina won 5 games more than maryann, and the sum of their games is 29.. 29-5/2= 12

Maryann won 12 games while Tina won 12+5= 17 games.

4 0
3 years ago
Read 2 more answers
Compute the directional derivative of the function g(x,y)= sin(π(x−5y)).
e-lub [12.9K]

Answer:

Step-by-step explanation:

The directional derivative of a function in a particular direction u is given as the dot product of the unit vector in the direction of u and the gradient of the function

g(x,y) = sin(π(x−5y)

∇g = [(∂/∂x)î + (∂/∂y)j + (∂/∂z)ķ] [sin(π(x−5y))

(∂/∂x) g = (∂/∂x) sin (πx−5πy) = π [cos(π(x−5y))]

(∂/∂y) g = (∂/∂y) sin (πx−5πy) = - 5π [cos (π(x−5y))]

∇g = π [cos(π(x−5y))] î - 5π [cos (π(x−5y))] j

∇g = π [cos (π(x−5y))] [î - 5j]

So, the question requires a direction vector and a point to fully evaluate this directional derivative now.

8 0
4 years ago
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