x+2 > 10 solves to x > 8 after we subtract 2 from both sides
So set A is the set of real numbers that are larger than 8. The value 8 itself is not in set A. The same can be said about 5 as well.
Set B is the set of values that are larger than 5 since 2x > 10 turns into x > 5 after dividing both sides by 2. The value x = 5 is not in set B since x > 5 would turn into 5 > 5 which is false. The values x = 6, x = 8, and x = 9 are in set B.
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Summarizing everything, we can say...
5 is not in set A. True
5 is in set B. False
6 is in set A. False
6 is not in set B. False
8 is not in set A. True
8 is in set B. True
9 is in set A. True
9 is not in set B. False
Answer:
A but I'm not so sure
Step-by-step explanation:
The point slope form of a straight line is y-y1 = m(x-x1)
y -(-3) = -7(x-5)
y + 3 = -7(x-5)
y = -7x + 35 - 3
y = -7x + 32
Answer:
x = 57°
Step-by-step explanation:
The angle not 76° or x° is 180-133 which is 47°. A triangles angles always sum up to 180° so:
76°+47°+x°=180°
123°+x°=180°
x°=57°
To factor using the reverse of the distributive property, find what common factor the numbers have and what common factor the variables have.
10.
-8x - 16
8 is a factor of both -8 and 16.
The first term has x, but the second term does not, so there is no common variable. The only common factor is 8, or -8.
Factor out a -8:
-8x - 16 = -8(x + 2)
To see if the factorization is correct, multiply the answer using the distributive property. If you get the original expression, then the factorization is correct.
11.
w^2 - 4w
The first term only has a factor of 1. The second term has a 4. There is no common factor between 1 and 4 except for 1, so there is no number you can factor out. The first term has w^2. The second term has w. Both terms have a common factor of w. We can factor out w from both terms.
w^2 - 4w = w(w - 4)
12.
4s + 10rs
4 and 10 have a common factor of 2.
s and rs have a common factor of s.
2 times s is 2s, so the common factor is 2s.
We now factor out 2s
4s + 10rs = 2s(2 + 5r)
