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3 years ago

9

PLEASE HELP !! DUE SOON ! :(

1 answer:

oksian1 [2.3K]3 years ago

4 0

Answer:

-3

Step-by-step explanation:

W = -3

X = 3

Z = -9

Y = 6

-3 + 3 = 0

-9 + 6 = -3

-3 + 0 = -3

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Christen sells boxes of cookies for $4 each. Rafael sells boxes of cookies for $7 each. Each of them sold the same dollar amount

KATRIN_1 [288]

Answer:

28$ and christen sold 7 boxes while Rafael sold 4

Step-by-step explanation:

lower common multiple so take 4 x 7 = 28 as then take the 28 and divide by how much Christen gets a box which is 4 and 28 divided by 4 is 7

3 0

3 years ago

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Given: KLMN is a trapezoid m∠N = m∠KML

horrorfan [7]

Answer:

The length of sides KM, LM and KN are $\sqrt{109}, \frac{48}{5}$ and 16 respectively. The area of KLMN is $\frac{192\sqrt{5}}{5}$ square unit.

Step-by-step explanation:

According to given information: KLMN is a trapezoid, ∠N= ∠KML, $\frac{LM}{KN}=\frac{3}{5}$ , ME ⊥ KN, KE=8 $ME=3\sqrt{5}$ .

Use pythagoras theorem is triangle EKM

$Hypotenuse^2=base^2+perpendicular^2$

$(KM)^2=(KE)^2+(ME)^2$

$(KM)^2=(8)^2+(3\sqrt{5})^2$

$KM^2=64+9(5)$

$KM=\sqrt{109}$

Let angle N and angle KML be θ.

Since angle KML and angle MKE are alternate interior angles, therefore angle MKE is θ.

In triangle KME,

$\tan\theta=\frac{3\sqrt{5} }{8}$ .... (1)

In triangle KNE,

$\tan\theta=\frac{3\sqrt{5} }{EN}$ .... (2)

Equate (1) and (2),

$\frac{3\sqrt{5} }{8}=\frac{3\sqrt{5} }{EN}$

$EN=8$

The length of side KN is

$KN=KE+EN=8+8=16$

Sides LM:KN are in the ratio 3:5. Let the side lengths are 3x and 5x respectively.

$5x=16$

$x=\frac{16}{5}$

$3x=3\times \frac{16}{5}=\frac{48}{5}$

The area of KLMN is

$Area=\frac{1}{2}(b_1+b_2)h$

$A=\frac{1}{2}\times (LM+KN)\times ME$

$A=\frac{1}{2}\times (\frac{48}{5}+16)\times 3\sqrt{5}$

$A=\frac{192\sqrt{5}}{5}$

Therefore length of sides KM, LM and KN are $\sqrt{109}, \frac{48}{5}$ and 16 respectively. The area of KLMN is $\frac{192\sqrt{5}}{5}$ square unit.

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4 years ago

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