-9(2p+1)
like this? or different
The square root of 1 is 1, but the square root of 18 needs to be explored. 18 is 9*2, and 9 is a perfect square. So let's rewrite our original problem using that fact:
![\sqrt{ \frac{1}{18} } = \sqrt{ \frac{1}{9*2} }](https://tex.z-dn.net/?f=%20%5Csqrt%7B%20%5Cfrac%7B1%7D%7B18%7D%20%7D%20%3D%20%5Csqrt%7B%20%5Cfrac%7B1%7D%7B9%2A2%7D%20%7D%20)
. We can pull out the square root of 1 as 1 and the square root of 9 as 3, leaving the 2 behind:
![\sqrt{ \frac{1}{9*2} } = \frac{1}{3} \sqrt{ \frac{1}{2} }](https://tex.z-dn.net/?f=%20%5Csqrt%7B%20%5Cfrac%7B1%7D%7B9%2A2%7D%20%7D%20%3D%20%5Cfrac%7B1%7D%7B3%7D%20%5Csqrt%7B%20%5Cfrac%7B1%7D%7B2%7D%20%7D%20%20%20)
. And there you go!
I’m not sure but I’m commenting Bc I really need an answer I’m so sorry
Answer:
- 7
- 4
- -7, 0, +9
Step-by-step explanation:
Hope this helps
Answer:
Step-by-step explanation:
7. Hope that helps !!