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il63 [147K]
3 years ago
5

Number c is really difficult

Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
6 0
Multiply each term in the equation by 4/1.
9-2y+2y+4=24

Combine like terms
13=24

Because the result is false, it is no solution.
You might be interested in
Write the equation that shows the relationship in the table
GenaCL600 [577]

Answer:

y= 20x

Step-by-step explanation:

40/2=100/5=200/10=20  linear function.

I hope this help you

8 0
3 years ago
Given the data shown below, which of the following is the best prediction for the number of years it will take for the populatio
aleksley [76]

We will have the following:

Using exponential regression we will have that the line of best fit will be:

f\mleft(x\mright)=8585.658603*1.399211892^x

Now, we will have that:

\begin{gathered} 300000=8585.658603*1.399211892^x\Rightarrow34.94199034=1.399211892^x \\  \\ \Rightarrow x=\frac{ln(34.94199034)}{1.399211892}\Rightarrow x= \end{gathered}

So, the approximation using linear regression gives us as solution approximately 29.7 years; thus the closest one to match is then

3 0
1 year ago
How many ways could you draw a single card from a 52 card deck and get either a heart or a king?
alekssr [168]
25 is the correct answer
3 0
3 years ago
Covert each into algebraic equations
marshall27 [118]

Answer:

1) 2x=4x-8

2) 4(x+2)=20

3) 2x-9=4(x+5)

3 0
2 years ago
Forty percent of households say they would feel secure if they had $50,000 in savings. you randomly select 8 households and ask
Kay [80]

Answer:

Let X be the event of feeling secure after saving $50,000,

Given,

The probability of feeling secure after saving $50,000, p = 40 % = 0.4,

So, the probability of not  feeling secure after saving $50,000, q = 1 - p = 0.6,

Since, the binomial distribution formula,

P(x=r)=^nC_r p^r q^{n-r}

Where, ^nC_r=\frac{n!}{r!(n-r)!}

If 8 households choose randomly,

That is, n = 8

(a) the probability of the number that say they would feel secure is exactly 5

P(X=5)=^8C_5 (0.4)^5 (0.6)^{8-5}

=56(0.4)^5 (0.6)^3

=0.12386304

(b) the probability of the number that say they would feel secure is more than five

P(X>5) = P(X=6)+ P(X=7) + P(X=8)

=^8C_6 (0.4)^6 (0.6)^{8-6}+^8C_7 (0.4)^7 (0.6)^{8-7}+^8C_8 (0.4)^8 (0.6)^{8-8}

=28(0.4)^6 (0.6)^2 +8(0.4)^7(0.6)+(0.4)^8

=0.04980736

(c) the probability of the number that say they would feel secure is at most five

P(X\leq 5) = P(X=0) + P(X=1) + P(X=2) + P(X=3) + P(X=4) + P(X=5)

=^8C_0 (0.4)^0(0.6)^{8-0}+^8C_1(0.4)^1(0.6)^{8-1}+^8C_2 (0.4)^2 (0.6)^{8-2}+8C_3 (0.4)^3 (0.6)^{8-3}+8C_4 (0.4)^4 (0.6)^{8-4}+8C_5(0.4)^5 (0.6)^{8-5}

=0.6^8+8(0.4)(0.6)^7+28(0.4)^2(0.6)^6+56(0.4)^3(0.6)^5+70(0.4)^4(0.6)^4+56(0.4)^5(0.6)^3

=0.95019264

8 0
3 years ago
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