1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Iteru [2.4K]
3 years ago
7

Log 3243 a)5 b)7 c)4 d)6

Mathematics
2 answers:
algol [13]3 years ago
4 0

Answer:

5

Step-by-step explanation:

Took the test

kramer3 years ago
3 0
What’s the question
You might be interested in
Find a.b.c if one of the angles is 150
Zepler [3.9K]
Triangle has 180 degrees
1 side=180
Then 180-150= 30 degrees
30/2 (for the other two sides)= 15
So, 150 degrees, 15 degrees and 15 degrees.
So it’s probably an isosceles triangle as the two bottom angles are the same number of degrees

Hope this helps :)
3 0
3 years ago
Evaluate the discriminant of the equation. Tell how many solutions each equation has and whether the solutions are real or imagi
cupoosta [38]

Answer:

D=-4<0, the equation has no real solutions, it has two imaginary solutions.

Step-by-step explanation:

The quadratic equation x^2 +4x+5=0 has coefficients

a=1,

b=4,

c=5.

The discriminant D is the expression

D=b^2-4ac.

Hence,

D=4^2-4\cdot 1\cdot 5=16-20=-4

Since the discriminant is negative, the equation has no real solutions, it has two imaginary solutions.

4 0
3 years ago
Read 2 more answers
Amer is a clerk. His group medical insurance costs $3,292 a year, of which the
choli [55]
She pays 40% so 3292 times by 0.40 gives you 1,316.80 is what she pays.
5 0
3 years ago
Three angles of a quadrilateral are 75,120, 90,then the fourth angle..​
Roman55 [17]

Answer:

75

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality<u> </u>

<u>Geometry</u>

  • Sum of Angles in a Quadrilateral: 360

Step-by-step explanation:

<u>Step 1: Set up</u>

75 + 120 + 90 + ∠4 = 360

<u>Step 2: Solve</u>

  1. Add:                                                                                                                   285 + ∠4 = 360
  2. [Subtraction Property of Equality] Subtract 285 on both sides:                   ∠4 = 75
5 0
3 years ago
REALLY NEED HELP:  The Venn Diagram shows a universe with 26 elements and two different outcomes: B and Y
Goshia [24]

Answer:

P(B|Y)=0.4

Step-by-step explanation:

We are given with a Venn diagram of a universe with 26 elements and two different outcomes: B and Y

And we are asked to find P(B|Y)

The formula for P(B|Y)= \frac{P(B\cap Y)}{P(Y)}

From Venn diagram, P(B\cap Y)=\frac{n(B\cap Y)}{26} =\frac{8}{26} =\frac{4}{13}

And P(Y)=\frac{n(Y)}{26}=\frac{8+12}{26}= \frac{20}{26}= \frac{10}{13}

Hence P(B|Y)=\frac{(\frac{4}{13})}{\frac{10}{13}} =\frac{4}{10}=0.4

6 0
3 years ago
Read 2 more answers
Other questions:
  • The perimeter of a rectangle is 68cm. The length is four cm. more than the width. Find the dimensions of the rectangle
    7·1 answer
  • How to write a standard form equation with an undefined slope?
    5·1 answer
  • What is p(king or club)?
    10·1 answer
  • A square has sides of 15 feet how much fencing would be needed
    10·1 answer
  • F(x) = 2x2 + 9x<br> Find f(10)
    6·1 answer
  • WRITE THE SUM OF THE NUMBERS AS THE PRODUCT OF THEIR GCF AND ANOTHER SUM 48+14
    8·1 answer
  • In the town of Westerly, Windsor Avenue and Orchid Drive are parallel. Main Street is perpendicular to both Windsor Avenue and O
    9·1 answer
  • Solve.<br><br> -5p + 28= 13<br><br> p =
    12·2 answers
  • The difference between a number and seven at least 12
    10·2 answers
  • Name the marked angle in 2 different ways.<br> N<br> M<br> L<br> K
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!