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julia-pushkina [17]
3 years ago
5

Games at the carnival cost $3 each. The prizes awarded to winners cost $150. How many games must be played to make at

Mathematics
1 answer:
natima [27]3 years ago
6 0

Answer:

219 games.

Step-by-step explanation:

Given the following data;

Cost of each game = $3

Cost of award = $150

Let x = number of games played.

Translating the word problem into an algebraic equation, we have;

3x - 150 \geq $507

<em>Rearranging the equation, we have;</em>

3x \geq 507 + 150

3x \geq 657

<em>Dividing both sides by 3, we have;</em>

x \geq \frac{657}{3}

x \geq 219

<em>Therefore, the number of games to be played in order to make $507 is at least 219 games. </em>

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7 1/10 , 7.108 , 57/8 , 7.79

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3 years ago
ПОЖАЛУЙСТА ПОМОГИТЕ РЕШИТЬ ДАЮ 23 ОЧКА!!!
posledela

(Простите, пожалуйста, мой английский. Русский не мой родной язык. Надеюсь, у вас есть способ перевести это решение. Если нет, возможно, прилагаемое изображение объяснит достаточно.)

Use the shell method. Each shell has a height of 3 - 3/4 <em>y</em> ², radius <em>y</em>, and thickness ∆<em>y</em>, thus contributing an area of 2<em>π</em> <em>y</em> (3 - 3/4 <em>y</em> ²). The total volume of the solid is going to be the sum of infinitely many such shells with 0 ≤ <em>y</em> ≤ 2, thus given by the integral

\displaystyle 2\pi \int_0^2 y \left(3-\frac34 y^2\right) \,\mathrm dy = 2\pi \left(\frac32 y^2 - \frac3{16} y^4\right)\bigg|_0^2 = 6\pi

Or use the disk method. (In the attachment, assume the height is very small.) Each disk has a radius of √(4/3 <em>x</em>), thus contributing an area of <em>π</em> (√(4/3 <em>x</em>))² = 4<em>π</em>/3 <em>x</em>. The total volume of the solid is the sum of infinitely many such disks with 0 ≤ <em>x</em> ≤ 3, or by the integral

\displaystyle \pi \int_0^3 \left(\sqrt{\frac43x}\right)^2 \,\mathrm dx = \frac{2\pi}3 x^2\bigg|_0^3 = 6\pi

Using either method, the volume is 6<em>π</em> ≈ 18,85. I do not know why your textbook gives a solution of 90,43. Perhaps I've misunderstood what it is you're supposed to calculate? On the other hand, textbooks are known to have typographical errors from time to time...

8 0
3 years ago
A test requires that you answer either part A or part B. Part A consists of 7 true-false questions, and part B consists of 5 mul
jeka94

Answer: 3253

Step-by-step explanation:

Given : A test requires that you answer either part A or part B.

Part A consists of 7 true-false questions.

i.e.  there are 2 choices to answer each question.

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Part B consists of 5 multiple-choice questions with one correct answer out of five.

i.e.  there are 5 choices to answer each question.

Now, the number of ways to answer Part B : 5^5=3125                           (2)

Now, the number of  different ways to completed answer sheets are possible=  128+3125=3253          [Add (1) and (2) ]

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4 years ago
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