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katen-ka-za [31]
3 years ago
7

Write a variable expression for each phrase

Mathematics
1 answer:
almond37 [142]3 years ago
7 0

Answer:

1.M+19

2. Z-8

3. N/3

4. 3/N

5. 5+a=x

6. 32g

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A simple random sample of 85 is drawn from a normally distributed population, and the mean is found to be 146, with a standard d
MatroZZZ [7]

The correct option is ''The value of 135 because it is not greater than 136.5 values is outside the 99% confidence interval for the population mean''

<h2>Given that,</h2>

A simple random sample of 85 is drawn from a normally distributed population, and the mean is found to be 146, with a standard deviation of 34.

<h3>We have to find,</h3>

Which of the following values is outside the 99% confidence interval for the population mean?

<h3>According to the question,</h3>

A simple random sample of 85 is drawn from a normally distributed population, and the mean is found to be 146, with a standard deviation of 34.

Sample space n = 85,

Mean = 146

And standard deviation = 34

Then, The standard error of the sample is,

= \dfrac{\sigma}{n}\\\\= \dfrac{34}{\sqrt{85}}\\\\= \dfrac{34}{9.21}\\\\= 3.6

Then, z-critical value for 99% is 2.58,

Margin of error = ±9.515

Confidence interval for lower bound is,

= 146 - 9.515 = 136.485

And confidence interval upper bound is,

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Here, 135 is less than the lower bound,

Therefore, 135 does not lie within a 99% confidence interval.

For more details about Lower bound refer to the link given below.

brainly.com/question/15974739

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