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Citrus2011 [14]
3 years ago
15

Answer quick please! Which equation represents a line with a slip of three and a y-intercept of 6?

Mathematics
1 answer:
MAVERICK [17]3 years ago
3 0

Answer:

Try letter A (Sorry if its not right)

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PLEASE ANSWER ASAP! MUST BE WITH WITH WITH WITH WWWWWIIIIIIIITTTTTHHHH AN EXPLANATION IN ORDER TO RECEIVE POINTS & BRAINLIES
Dahasolnce [82]
Easy peasy pumpin easy

split it up (make in to net and unfold or something)

2 triangles (identical)
2 side rectangles (identical
1 base

area of rectangle=lh or wl etc
area of triangle=1/2bh


triangles
b=16
h=6
area of triangle=1/2*16*6=48
times 2 since 2 of them
48*2=96

2 side rectangles
10 by 7
10*7=70
times 2 since 2 of them
70*2=140

base
16by 7
16*7=112



add them
96+140+112=348

answer is C
4 0
3 years ago
there is a line that includes two point (-1,0) and has a slope of 19. What is its equation in slope-intercept form?​
shusha [124]

Answer:

Step-by-step explanation:

m = 19 ;   (-1,0)

y - y₁ = m (x - x₁)

y - 0 = 19 (x - [-1] )

     y = 19 ( x + 1 )

    y = 19x + 19

4 0
3 years ago
What's 5 divided by 3 1/3?
Dafna11 [192]

Answer: 3/2

Step-by-step explanation:

We can start by converting 3 1/3 to an improper fraction. Since 3 is equal to 9/3, 3 1/3 would be equal to 9/3 + 1/3 = 10/3.

Therefore, we are doing \frac{5}{\frac{10}{3}}.

Dividing 5 by 10/3 is the same as multiplying 5 and the reciprocal of 10/3, which is 3/10.

5*3/10 = 15/10 = 3/2.

6 0
2 years ago
PLZZZ HURRYYY ILL GIVE YOU BRAINIEST<br><br><br> What are the x-intercepts?
Alinara [238K]

Answer:

The x-intercepts are 0, 1, 2, 2.2

Step-by-step explanation:

Hope this helps if it answers your question

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6 0
3 years ago
A 12 vdc power supply powers a blue high intensity led with a forward voltage of 4.5 volts. The led is rated to withstand a maxi
dimulka [17.4K]

Answer:

Resister of 0.15 W is to be added.

Step-by-step explanation:

In a given circuit we have the attachments

A power supply of 12 V

High intensity LED with forward voltage = 4.5V

LED is rated to withstand a maximum current of 20 mA or 20.10^{-30} A

We have to calculate the size of a resister to be connected in series.

Here we will apply the Ohm's law for the calculations

Total voltage of the circuit = voltage of LED + voltage across resistance.

12=4.5+20.10^{-3}.r

r = (12 - 4.5)/20.10^{-3}

r = 7.5×10^{3}/20 = 375 ohm

Therefore power of the resistance = i².r

P=i^{2}\times r

         =(20\times 10^{-3})^{2}\times 375

        = 0.15 W

Therefore a resister of 0.15 W is to be added.

6 0
3 years ago
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