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Volgvan
3 years ago
9

What is the product? 2x+8 x2 + 3x-4 x(x-4)(x-1) 20x+4) 2 (x+4)(x-4) 2x(x-1) 2x(x+4)​

Mathematics
2 answers:
guajiro [1.7K]3 years ago
7 0

=−640x10+1280x9+19904x8−40728x7−144488x6+323904x5−162304x4+1024x3+2048x2

step by step

(2x+8x2+3x−4x(x−4)(x−1)(20)x+4)(2)(x+4)(x−4)(2)x(x−1)(2)x(x+4)

=((2x+8x2+3x−4x(x−4)(x−1)(20)x+4)(2)(x+4)(x−4)(2)x(x−1)(2)x)(x+4)

=((2x+8x2+3x−4x(x−4)(x−1)(20)x+4)(2)(x+4)(x−4)(2)x(x−1)(2)x)(x)+((2x+8x2+3x−4x(x−4)(x−1)(20)x+4)(2)(x+4)(x−4)(2)x(x−1)(2)x)(4)

=−640x10+3840x9+4544x8−58904x7+91128x6−40608x5+128x4+512x3−2560x9+15360x8+18176x7−235616x6+364512x5−162432x4+512x3+2048x2

=−640x10+1280x9+19904x8−40728x7−144488x6+323904x5−162304x4+1024x3+2048x2

Oduvanchick [21]3 years ago
4 0
The product is the same as the answer
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7 0
3 years ago
Use the following compound interest formula to complete the problem. a = p (1 startfraction r over n endfraction) superscript n
ioda

The difference between the amount in two cards of Sandra after 4 years will be $125.58 approx.

<h3>How to find the compound interest?</h3>

If n is the number of times the interested is compounded each year, and 'r' is the rate of compound interest annually, then the final amount after 't' years would be:

a = p(1 + \dfrac{r}{n})^{nt}

For this case, Sandra has got 2 credit cards p and q. Calculating the final amount both card will have after 4 years:

  • Case 1: For card p:

Initial amount = p = $726.19

The rate of interest is r = 10.19% = 10.19/100 = 0.1019 (converted percent to decimal)

Years for which amount is compounded = 4 years, Thus, t = 4

The interest is compounding semiannually, that means twice per year, thus, n = 2

Thus, the final amount in card p after 4 years would be:

a = p(1 + \dfrac{r}{n})^{nt}\\\\a = 726.19(1+0.1019/2)^{2 \times 4} \\\\a= 726.19 \times (1.05095)^8 \approx 1080.70\: \rm (in \: dollars)

  • Case 2: For card q:

Initial amount = p = $855.20

The rate of interest is r = 8.63% = 8.63/100 = 0.0863 (converted percent to decimal)

Years for which amount is compounded = 4 years, Thus, t = 4

The interest is compounding monthly, that means twelve times per year, thus, n = 12

Thus, the final amount in card q after 4 years would be:

a = p(1 + \dfrac{r}{n})^{nt}\\\\a = 855.20(1+0.0863/12)^{12 \times 4} \\\\a= 855.20\times (1.0071916)^{48} \approx 1206.28\: \rm (in \: dollars)

Clearly card q has more amount than card p at the end of 4 years.

The difference is: 1206.28 - 1080.70 = 125.58 (in dollars)

Learn more about compound interest here:

brainly.com/question/1329401

4 0
3 years ago
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