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Andrew [12]
4 years ago
9

Jim invested $6,000 at 4% simple interest. How many interest will he earn the first year ?

Mathematics
1 answer:
dmitriy555 [2]4 years ago
6 0
<span>$6000(0.04)=$24
He would earn $24 the first year at 4% simple interest.</span>
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ASAP!! Please help me. I will not accept nonsense answers, but will mark as BRAINLIEST if you answer is correctly with solutions
Sedaia [141]

Answer:

f(x) = 2(x –3)²

Step-by-step explanation:

f(x) = 2x² – 12x + 18

The vertex form of the above expression can be obtained as follow:

f(x) = 2x² – 12x + 18

Factorise

f(x) = 2(x² – 6x + 9)

Next, we shall simplify x² – 6x + 9 by factorisation method.

This is illustrated below:

x² – 6x + 9

Multiply the first term i.e x² and last term i.e 9 together. The result is 9x².

Next, find two factors of 9x² such that their sum will result to the 2nd term i.e –6x in the expression above.

The factors are –3x and –3x

Next, replace –6x with –3x and –3x in the equation above as shown below:

x² – 6x + 9

x² – 3x –3x + 9

Factorise

x(x – 3) –3(x –3)

(x –3)(x –3)

(x –3)²

f(x) = 2x² – 12x + 18

f(x) = 2(x² – 6x + 9)

f(x) = 2(x –3)²

Therefore, the vertex form of the function f(x) = 2x² – 12x + 18 is

f(x) = 2(x –3)²

4 0
3 years ago
Which of the following is the definition of y-intercept? the value where the line crosses the x-axis the value where the line cr
Trava [24]

Answer:the value where the line crosses the y axis

Step-by-step explanation:

its crossing through the y-axis not the x-axis because. The y-intercept is where the line crosses the y-axis.  for example, you see the line cuts across the y-axis at -2. This makes our y-intercept -2.

3 0
3 years ago
I need help please, I am so confused.​
vazorg [7]

Answer:

\begin{tabular}{| c | c | c |}\cline{1-3} Equation & x-intercepts & x-coordinate of vertex\\\cline{1-3} $y=x(x-2)$ & $x=0, x=2$ & $x=1$\\\cline{1-3} $y=(x-4)(x+5)$ & $x=-5, x=4$ & $x=-0.5$\\\cline{1-3} $y=-5x(x-3)$ & $x=0, x=3$ & $x=1.5$\\\cline{1-3} \end{tabular}

Step-by-step explanation:

x-intercepts are when the curve intercepts the x-axis, so when y =0.

Therefore, to find the x-intercepts, substitute y = 0 and solve for x.

The vertex is the turning point:  the minimum point of a parabola that opens upward, and the maximum point of the parabola that opens downward.  As a parabola is symmetrical, the x-coordinate of the vertex is the midpoint of the x-intercepts.

Equation:  y=x(x-2)

\implies x(x-2)=0

\implies x=0

\implies (x-2)=0 \implies x=2

Therefore, the x-intercepts are x = 0 and x = 2

The midpoint of the x-intercepts is x = 1, so the x-coordinate of the vertex is x = 1

Equation: y=(x-4)(x+5)

\implies (x-4)(x+5)=0

\implies (x-4)=0 \implies  x=4

\implies (x+5)=0 \implies x=-5

Therefore, the x-intercepts are x = -5 and x = 4

The midpoint of the x-intercepts is x = -0.5, so the x-coordinate of the vertex is x = -0.5

Equation: y=-5x(3-x)

\implies -5x(3-x)=0

\implies -5x=0 \implies x=0

\implies (3-x)=0 \implies x=3

Therefore, the x-intercepts are x = 0 and x = 3

The midpoint of the x-intercepts is x = 1.5, so the x-coordinate of the vertex is x = 1.5

\begin{tabular}{| c | c | c |}\cline{1-3} Equation & x-intercepts & x-coordinate of vertex\\\cline{1-3} $y=x(x-2)$ & $x=0, x=2$ & $x=1$\\\cline{1-3} $y=(x-4)(x+5)$ & $x=-5, x=4$ & $x=-0.5$\\\cline{1-3} $y=-5x(x-3)$ & $x=0, x=3$ & $x=1.5$\\\cline{1-3} \end{tabular}

4 0
2 years ago
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