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2 years ago

12

Change fraction ( 11/4) from an improper fraction to a mixed number.

1 answer:

leva [86]2 years ago

7 0

Answer:

Have a nice day :)

Step-by-step explanation:

To convert 11/4 into a mixed number, we need to divide 11 by 4 and get the values of quotient and remainder after performing division. When we divide 11/4, we get 2 as the quotient and 3 as the remainder. Now use the calculator to convert the following improper fractions to mixed fractions: 45/6

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50 points and BRAINLIEST<br><br> .15m - .13m = 69.96 - 55.96

weeeeeb [17]

Answer:

m=7

Step-by-step explanation:

15m−13m=69.96−55.96

Step 1: Simplify both sides of the equation.

15m−13m=69.96−55.96

15m+−13m=69.96+−55.96

(15m+−13m)=(69.96+−55.96)(Combine Like Terms)

2m=14

2m=14

Step 2: Divide both sides by 2.

2m

2

=

14

2

5 0

3 years ago

What is 2(x -3) = 7 (x+24)

amm1812

Answer:

x = -34.8

Step-by-step explanation:

<h2><u>solve the equation</u></h2>

2(x-3)

= 2x - 6

7(x + 24 )

= 7x + 168

put the equation together

2x - 6 = 7x + 168

now make x subject of formula:

2x - 7x = 168 +6

-5x = 174

x = 174/ -5

<h3><u>x = -34.8 </u></h3>

3 0

3 years ago

Read 2 more answers

Which choice is equivalent to

Masja [62]

Answer: it’s 8y-20

Step-by-step explanation:

7 0

3 years ago

F(x)=-x-2<br> G(x)= x^2 + 1-x<br> Find (f x g)(3)

nata0808 [166]

Answer:

-36

Step-by-step explanation:

le x be 2 then

f(x) = -2-2 =-4

g(x)= 2square +1-2 =3

to find:(f×g)(3)

(-4×3)(3)

=-36

3 0

2 years ago

Solve the problem. If s is a distance given by s(t) = + + 40 + 10. find the acceleration, alt). Q ald) = 10 ald) = 2t + 4 O alt)

QveST [7]

Answer:

C

Step-by-step explanation:

Remember that if s(t) is a position function then:

$v(t)=s'(t)$ is the velocity function and

$a(t)=s''(t)$ is the acceleration function.

So, to find the acceleration, we need to solve for the second derivative of our original function. Our original function is:

$s(t)=t^2+4t+10$

So, let's take the first derivative first with respect to t:

$\frac{d}{dt}[s(t)]=\frac{d}{dt}[t^2+4t+10]$

Expand on the right:

$s'(t)=\frac{d}{dt}[t^2]+\frac{d}{dt}[4t]+\frac{d}{dt}[10]$

Use the power rule. Remember that the derivative of a constant is 0. So, our derivative is:

$v(t)=s'(t)=2t+4$

This is also our velocity function.

To find acceleration, we want to second derivative. So, let's take the derivative of both sides again:

$\frac{d}{dt}[s'(t)]=\frac{d}{dt}[2t+4]$

Again, expand the right:

$s''(t)=\frac{d}{dt}[2t]+\frac{d}{dt}[4]$

Power rule. This yields:

$a(t)=s''(t)=2$

So, our answer is C.

And we're done!

6 0

3 years ago