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3 years ago

Which of the following are statistical questions? Select all that apply.

2 answers:

8 0

The correct answer would be all the answers . Statistics is data/numbers of recorded results . All four choices can be statistical data

user100 [1]3 years ago

5 0

Answer:

I think A and B

Step-by-step explanation:

• A statistical question is a question that has more than one possible answer ( and can be answered by collecting data) where there will be variability in the data. for instance an example would be " How old are the students in this room?"

• However a non statical question has only one answer for instance "How old are you?"

both a and b dont have specific answers because it's not talking about a specific high school students or a specific soccer team. i would guess those are correct, but using the information from above you can also see what you think! hope this helps :)

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What is the quotient written in scientific notation?

sukhopar [10]

A. 2.4×10^−10
.................

6 0

3 years ago

The mean waiting time at the drive-through of a fast-food restaurant from the time the food is ordered to when it is received is

alexira [117]

Answer:

a) And if we replace we got: $\bar X= 78$

$s = 15.391$

b) $78-3.25\frac{15.391}{\sqrt{10}}=62.182$

$78-3.25\frac{15.391}{\sqrt{10}}=93.818$

So on this case the 99% confidence interval would be given by (62.182;93.818)

Step-by-step explanation:

Dataset given: 109 67 58 76 65 80 96 86 71 72

Part a

For this case we can calculate the sample mean with the following formula:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

And if we replace we got: $\bar X= 78$

And the deviation is given by:

$s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And if we replace we got $s = 15.391$

Part b

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=10-1=9$

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,9)".And we see that $t_{\alpha/2}=3.25$

Now we have everything in order to replace into formula (1):

$78-3.25\frac{15.391}{\sqrt{10}}=62.182$

$78-3.25\frac{15.391}{\sqrt{10}}=93.818$

So on this case the 99% confidence interval would be given by (62.182;93.818)

8 0

3 years ago

jasmine buys 21 cans of dog food. She gives 1/3 of the cans to her neighbor and she keeps the rest of the cans for her puppy. Ja

Llana [10]

21 cans of dog food.

She gives 21/3, or 7 cans to her neighbor.

She now has 21 - 7, or 14 cans for her puppy.

Her puppy eats 4/7 cans a day.

$14 \times \frac{4}{7} =2\times 4= \boxed{\bf{8}}$

Jasmine has 8 days supply of dog food for her puppy.

4 0

3 years ago

Please help! Picture attached. (7th grade)

Hunter-Best [27]

Option B. 2 because 2-8
------- = -3
2

8 0

3 years ago

Read 2 more answers

Find the center of a circle with the equation: x2 y2−32x−60y 1122=0 x 2 y 2 − 32 x − 60 y 1122 = 0

mixas84 [53]

The equation of a circle exists:

$$(x-h)^2 + (y-k)^2 = r^2$ , where (h, k) be the center.

The center of the circle exists at (16, 30).

<h3>What is the equation of a circle?</h3>

Let, the equation of a circle exists:

$$(x-h)^2 + (y-k)^2 = r^2$ , where (h, k) be the center.

We rewrite the equation and set them equal :

$$(x-h)^2 + (y-k)^2 - r^2 = x^2+y^2- 32x - 60y +1122=0$

$$x^2 - 2hx + h^2 + y^2 - 2ky + k^2 - r^2 = x^2 + y^2 - 32x - 60y +1122 = 0$

We solve for each coefficient meaning if the term on the LHS contains an x then its coefficient exists exactly as the one on the RHS containing the x or y.

-2hx = -32x

h = -32/-2

⇒ h = 16.

-2ky = -60y

k = -60/-2

⇒ k = 30.

The center of the circle exists at (16, 30).

To learn more about center of the circle refer to:

brainly.com/question/10633821

#SPJ4

7 0

2 years ago