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enyata [817]
3 years ago
5

If a_1=5a

Mathematics
1 answer:
Vikki [24]3 years ago
7 0

Answer:

a_5 = 21

Step-by-step explanation:

Arithmetic sequence:

In an arithmetic sequence, the difference between consecutive terms is always the same, and this difference is called common difference.

The nth term of an arithmetic sequence is given by:

a_n = a_1 + d(n-1)

In which a_1 is the first term and d is the common difference.

In this question:

a_1 = 5, d = 4. So

a_n = a_1 + d(n-1)

a_n = 5 + 4(n-1)

Find the value of a_5

a_n = 5 + 4(n-1)

a_5 = 5 + 4(5-1) = 5 + 16 = 21

So

a_5 = 21

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The center going through (-9,2) gives you A and B
(x - - 9)^2 + (y - 2)^2 = r^2
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Going from the center to the given point gives you the radius. We need the r^2 which is the way the distance formula works: it will give you r^2. c = r^2

d^2 = (x2 - x1)^2 + (y2 - y1)^2
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