HELP PLSS!!

Mathematics

1 answer:

erma4kov [3.2K]2 years ago

8 0

Answer:

Step-by-step explanation:

The average rate of change of f(x) in the closed interval [ a, b ] is

$\frac{f(b)-f(a)}{b-a}$

Here [ a, b ] = [ 3, 6 ] , then

f(b) = f(6) = 6² + 3(6) + 2 = 36 + 18 + 2 = 56

f(a) = f(3) = 3² + 3(3) + 2 = 9 + 9 + 2 = 20 , then

average rate of change = $\frac{56-20}{6-3}$ = $\frac{36}{3}$ = 12

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Answer number 1 please.

Minchanka [31]

$\sf {a}^{2} = {13}^{2} - {5}^{2}$

Formula :

Base²= Hypotenuse² - Perpendicular ²

$\\ \\$

$\hookrightarrow\sf {a}^{2} = {13}^{2} - {5}^{2}$

$\\ \\$

$\hookrightarrow\sf {a}^{2} =169 - 25$

$\\ \\$

$\hookrightarrow\sf {a}^{2} =144$

$\\ \\$

$\hookrightarrow\sf {a} = \sqrt{144}$

$\\ \\$

$\hookrightarrow\sf {a} = \sqrt{12 \times 12}$

$\\ \\$

$\hookrightarrow\sf {a} = 12$

Remember the a² in formula has nothing to do with the a we have to find. :)

6 0

2 years ago

Read 2 more answers

arrange the expressions in the correct sequence to rationalize the denominator of the expression -(2)/(\sqrt(x+y-2)-\sqrt(x+y+2)

cupoosta [38]

We have to rationalize the denominator:
$\frac{-2}{ \sqrt{x+y-2} - \sqrt{x+y+2} } = \\ \frac{-2}{ \sqrt{x+y-2} - \sqrt{x+y+2} }* \frac{ \sqrt{x+y-2}+ \sqrt{x+y+2} }{ \sqrt{x+y-2}+ \sqrt{x+y+2} }= \\ \frac{-2*( \sqrt{x+y-2}+ \sqrt{x+y+2}) }{x+y-2-(x+y+2)}= \\ \frac{-2*( \sqrt{x+y-2}+ \sqrt{x+y+2}) }{x+y-2-x-y-2}= \\ \frac{-2*( \sqrt{x+y-2}+ \sqrt{x+y+2} }{-4}= \\ \frac{ \sqrt{x+y-2}+ \sqrt{x+y+2} }{2}$