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kramer
3 years ago
14

Obie Trice

Mathematics
1 answer:
Dovator [93]3 years ago
3 0

Answer:

they want shady im chop liver come on dip im on your lips its time to settle all my law suites frick you debby

Step-by-step explanation:

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Please answer number 12. Very urgent!! 18 points!
Ksenya-84 [330]

Answer:

10 5/12

When the numerator is larger than the denominator, we take  groups of whole fractions  (The numerator and denominator are equal) and add 1 to the whole number for each group. Whatever remains when we no longer have the numerator larger than the denominator is left as a fraction.

Step-by-step explanation:

6 3/4 + 3  2/3

We need to get a common denominator

The common denominator is 12

We need to rename the fractional parts  to out of 12

6 3/4 = 6 3/4*3/3 = 6 9/12

3 2/3 = 3 2/3*4/4 = 3 8/12

6 9/12+ 3 8/12

9 17/12

But the numerator is larger than the denominator

We take 12/12 from the fraction  and add it to the whole number

9 17/12-12/12  +1

9+1 5/12

10 5/12

4 0
4 years ago
Translate the phrase to an algebraic expression. (Use l for length and w for width.)
damaskus [11]
Answer:
\frac{l + w}{6}
Explanation:
The sum of two numbers is the result of when they are added up. So the "sum of the length and width" is the length + width or l + w. One-sixth of the sum of the length and width is l+w divided by 6. so you get:

\frac{l + w}{6}

Hope this helps!
5 0
4 years ago
Plz help will mark brainliest if correct answer ​
Vladimir79 [104]

Answer:

73

Step-by-step explanation:

4 0
3 years ago
A jeweler has 10 different gems he uses to create bracelets. If his bracelets have 6 different gems apiece, how many different s
Flauer [41]
He can make 10 different styles of bracelet
5 0
4 years ago
Read 2 more answers
A hyperbola has its center at (0,0), a vertex of (20,0 and an asymptote of y= 13/20x. find the equation that describes the hyber
photoshop1234 [79]

Answer:

\frac{x^2}{20^2} -\frac{y^2}{13^2} =1

Step-by-step explanation:

Given that a hyperbola has its centre at (0,0)

Asymptote = y =13x/20

Vertex is on x axis thus a =20

Hence hyperbola will have equation as

\frac{x^2}{20^2} -\frac{y^2}{b^2} =1

Asymptotes would be

\frac{x^2}{20^2} -\frac{y^2}{b^2} =0

Or y=bx/20

Comparing with given equation we get b =13

Hence asymptote would have equation as

\frac{x^2}{20^2} -\frac{y^2}{13^2} =1\\\frac{x^2}{400} -\frac{y^2}{169} =1

4 0
3 years ago
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