PLEASE HELP! URGENT!

A study participant was asked to observe circular images and determine if they were the same size as a 10 cm2 circle. circles wi

Neko [114]

For the answer to the question above, according to Weber's law, the perceptible differences are proportional to the initial perception. So, with just a 10% increase in area was perceptible, but an increase of 1-9% in the area is considered imperceptible. The 9% increase in area reflected by 200 to 218 would be perceived as the same size as before.
The answer is 218

6 0

3 years ago

Can you share 1 one with 6 groups

PolarNik [594]

Answer:

no

Step-by-step explanation:

not only the mean time I am lilltle busy with the mean time I am lilltle busy with the mean time I am lilltle busy with the mean time I am lilltle busy with the mean time I was just a days at 8 I want MVP award for this calendar to the Peaco to the Peaco I want MVP if anyone has questions about HTML5 is not

4 0

3 years ago

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Daniel is paid $10 per week for selling newspaper subscriptions. He is also paid $3.50 for each new customer (x) that signs up f

In-s [12.5K]

First, we need to set up the equation.

y = amount

x = new customer

Daniel gets 10 dollars each week. Let's think of this as a base pay, there's no variable to it.

So we start with 10.

Next, we have 3.50 dollars each week for each new customer.

So that would be 3.50 times each new customer which would become 3.50x

When you put those two together, you get y = 10 + 3.50x.

4 0

3 years ago

Suppose 300 nursing students took a certification test that is worth 100 points.

Alja [10]

Answer:

225 students scored 65 or better and 75 students scored 88 or better.

Step-by-step explanation:

We are given that The five-number summary for the scores of 300 nursing students are given :

Minimum = 40

$Q_1 = 65$

Median = 82

$Q_3 = 88$

Maximum = 100

$Q_1$ is the first quartile and is the median of the lower half of the data set. 25% of the numbers in the data set lie below $Q_1$ and about 75% lie above $Q_1$ .

$Q_3$ is the third quartile and is the median of the upper half of the data set. 75% of the numbers in the data set lie below $Q_3$ and about 25% lie above $Q_3$

i) .About how many students scored 65 or better?

$Q_1 = 65$

Since we know that 75% lie above $Q_1$ .

So, Number of students scored 65 or better = $75\% \times 300 = \frac{75}{100} \times 300 =225$

ii)About how many students scored 88 or better?

$Q_3 = 88$

Since we know that 25% lie above $Q_3$

So, Number of students scored 88 or better = $25\% \times 300 = \frac{25}{100} \times 300 =75$

Hence 225 students scored 65 or better and 75 students scored 88 or better.

7 0

4 years ago

Which expression has a positive quotient?

svp [43]

Answer:

Only 1st option Negative three-fourths divided by Negative two-thirds has positive quotient.

Option A is correct.

Step-by-step explanation:

We will solve to find out Which expression has a positive quotient.

We know the division rule: $\frac{-a}{-b}=\frac{a}{b}$ and $\frac{-a}{b}=\frac{-a}{b}$

We will use these rules

1) Negative three-fourths divided by Negative two-thirds

$=\frac{-\frac{3}{4} }{-\frac{2}{3} }\\=-\frac{3}{4}\times -\frac{3}{2}\\=\frac{9}{8}$

The quotient is positive.

2) Negative StartFraction 1 over 8 EndFraction divided by 3 and one-fifth

$\frac{-\frac{1}{8} }{3\frac{1}{5} }\\=\frac{-\frac{1}{8} }{\frac{16}{5} }\\=-\frac{1}{18} \times \frac{5}{16}\\=-\frac{5}{288}$

The quotient is negative.

3) 2 and StartFraction 2 over 7 EndFraction divided by negative one-fifth

$\frac{2\frac{2}{7} }{-\frac{1}{5} }\\= \frac{\frac{16}{7} }{-\frac{1}{5} }\\=\frac{16}{7} \times -5\\=-\frac{80}{7}$

The quotient is negative.

4) Negative 6 divided by Five-thirds

$\frac{-6}{\frac{5}{3} }\\=-6 \times \frac{3}{5}\\=-\frac{18}{5}$

The quotient is negative.

So, only 1st option Negative three-fourths divided by Negative two-thirds has positive quotient.

Option A is correct.

4 0

3 years ago

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