How would i solve this?
1 answer:
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Answer:
Options A and C are the only polynomials.
Step-by-step explanation:
We know that,
A polynomial is an expression having more than one algebraic terms.
<em>It is of the form, ,</em>
<em>where the coefficients for i = 1,2,3,4,... are real numbers and the degree 'n' are natural numbers.</em>
So, from the options, we see that,
Options B, D and E are not of the above form and so are not polynomials.
Thus, options A and C are the only polynomials.
If is a polynomial, then the zeros of
are the values of
that satisfy
.
So for (1), the zeros of are the solutions to
You can think of the multiplicity of each root as the number of times a root satisfies this equation. In this case, the multiplicity of each root is 1, because there is only one factor of or
or
.
For (2), the zeros of are the solutions to
and the multiplicity of the zero is 2 because there are two factors of
in
. The multiplicity of the other roots would be 1.