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Hitman42 [59]
3 years ago
12

PLEASE HELP.. THIS IS DUE TONIGHT I WILL MARK BRAINIEST

Mathematics
1 answer:
umka2103 [35]3 years ago
6 0

Answer:

1. Slope is -3

2. 85 meters high

3. y=60x

4. There are no solutions (C)

5. B Lana saves better at 40 dollars weekly while Elena saves 37 per week

Step-by-step explanation:

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Operations with rational expressions
Scorpion4ik [409]

$\frac{50-2 w^{2}}{3 w^{2}+9 w-30} \cdot \frac{w^{2}+5 w-14}{6 w-30}=-\frac{w+7}{9}

Solution:

Given expression:

$\frac{50-2 w^{2}}{3 w^{2}+9 w-30} \cdot \frac{w^{2}+5 w-14}{6 w-30}

To solve the given expression:

First simplify: \frac{50-2 w^{2}}{3 w^{2}+9 w-30}

$\frac{50-2 w^{2}}{3 w^{2}+9 w-30}=-\frac{2(w+5)(w-5)}{3(w-2)(w+5)}

Cancel the common factor (w + 5).

                      $=-\frac{2(w-5)}{3(w-2)}

Now substitute this in the given expression.

$\frac{50-2 w^{2}}{3 w^{2}+9 w-30} \cdot \frac{w^{2}+5 w-14}{6 w-30}=-\frac{2(w-5)}{3(w-2)} \cdot \frac{w^{2}+5 w-14}{6 w-30}

Multiply the fractions \frac{a}{b} \cdot \frac{c}{d}=\frac{a \cdot c}{b \cdot d}

                               $=-\frac{2(w-5)\left(w^{2}+5 w-14\right)}{3(w-2)(6 w-30)}

Factor the denominator 3(w-2)(6 w-30) =18(w-2)(w-5)

                               $=-\frac{2(w-5)\left(w^{2}+5 w-14\right)}{18(w-2)(w-5)}                        

Cancel the common factor 2(w – 5).

                               $=-\frac{w^{2}+5 w-14}{9(w-2)}

Factor the numerator w^{2}+5 w-14=(w-2)(w+7)

                               $=-\frac{(w-2)(w+7)}{9(w-2)}

Cancel the common factor (w – 2).

                               $=-\frac{w+7}{9}

$\frac{50-2 w^{2}}{3 w^{2}+9 w-30} \cdot \frac{w^{2}+5 w-14}{6 w-30}=-\frac{w+7}{9}

3 0
3 years ago
The ratio of girls to boy in the junior high band is 5 to 7. At the beginning of the year, there were 72 students in the band. B
kvasek [131]
I don't really understand this question do u have a pic?
5 0
4 years ago
M1-(17x+1) and m2(20x-14) find m2
Vadim26 [7]

Answer:

If your goal is to simplify it, then it would be

38Fmnsxi

7 0
3 years ago
Sophia want to rent an apartment she visits apartment A Whitehall charges $100 for a one time deposit and $400 per month for ren
Alex

Answer:

The inequality in this case is 100 + 400*t > 500 + 350*t and for B to be cheaper Sophia has to rent it for more than 8 months.

Step-by-step explanation:

In order to write the inequality we first need to write two equations one for each apartment. For apartment A we have a fixed cost of $100 and a variable cost of $400 that varies according to the time living in there, so we have:

rent = 100 + 400*t

For apartment B we have a fixed cost of $500 and a variable cost of $350 that varies according to the time living in there, so we have:

rent = 500 + 350*t

In order for the total paid in B to be less than for the one in A we need to satisfy the following inequality:

100 + 400*t > 500 + 350*t

400*t - 350*t > 500 - 100

50*t > 400

t > 400/50

t > 8 months

The inequality in this case is 100 + 400*t > 500 + 350*t and for B to be cheaper Sophia has to rent it for more than 8 months.

8 0
3 years ago
Please help ! I only have 30 more minutes
navik [9.2K]

Answer:

1.5, negative, negative

4 0
3 years ago
Read 2 more answers
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