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nevsk [136]
3 years ago
5

Yes or no is the following a function help!

Mathematics
2 answers:
ira [324]3 years ago
7 0
The guy above me is correct
slamgirl [31]3 years ago
3 0

Answer:

Yes

Step-by-step explanation:

This is a function because each input has an output

You might be interested in
A 90 pound object on earth weighs 15 pounds on the moon if an object weighs 156 pounds on earth how much is a win the moon
Tanya [424]
26 pounds

Because

E is the objects gravity in earth
M objects gravity on moon

E=km
Or
90=15k

90/15=15k/15

6=k

156=6m

156/6 =6m/6

26=m

Have a great day
7 0
3 years ago
Provide me three coordinate points for the following, given the Slope and Y-intercept. 5. Slope = 7/9, Y intercept = 12(give me
madam [21]

Since we have that the slope is m = 7/9 and the y-intercept is b = 12, we can write the equation of the line in slope-intercept form:

\begin{gathered} y=mx+b \\ \Rightarrow y=\frac{7}{9}x+12 \end{gathered}

to find three coordinate points, we can use arbitrary values on x to get the y-coordinate. To make things easier, let's use x = 9, 18 and 27:

\begin{gathered} x=9 \\ \Rightarrow y=\frac{7}{9}(9)+12=7+12=19 \\ x=18 \\ \Rightarrow y=\frac{7}{9}(18)+12=7(2)+12=14+12=26 \\ x=27 \\ \Rightarrow y=\frac{7}{9}(27)+12=7(3)+12=21+12=33 \end{gathered}

therefore, the line with slope m = 7/9 and y-intercept 12 passes through the three points (9,19), (18,26) and (27,33)

8 0
1 year ago
I need help with the question
Katena32 [7]

Answer:

6, 8, 4

Step-by-step explanation:

the answers are as follows

a. 6

b. 8

c. 4

3 0
3 years ago
the perimeter of the floor of a room is 18 metre and its height is 3 cm what is the area of 4 walls of the room​
Lina20 [59]

Note: The height of the room must be 3 m instead of 3 cm because 3 cm is too small and it cannot be the height of a room.

Given:

Perimeter of the floor of a room = 18 metre

Height of the room = 3 metre

To find:

The area of 4 walls of the room.

Solution:

We know that, the area of 4 walls of the room is the curved surface area of the cuboid room.

The curved surface area of the cuboid is

C.S.A.=2h(l+b)

Where, h is height, l is length and b is breadth.

Perimeter of the rectangular base is 2(l+b). So,

C.S.A.=\text{Perimeter of the base} \times h

Putting the given values, we get

C.S.A.=18\times 3

C.S.A.=54

Therefore, the area of 4 walls of the room is 54 sq. metres.

7 0
3 years ago
Fractions greater than one 7-4
Oksana_A [137]
N > 1/3
n = 1/4

sorry if I was wrong
5 0
3 years ago
Read 2 more answers
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