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barxatty [35]
3 years ago
5

What is the area of the shaded region?

Mathematics
2 answers:
suter [353]3 years ago
7 0
21.5 is the answer I got
Tresset [83]3 years ago
5 0

Answer:

21.5 \:  {cm}^{2}

Step-by-step explanation:

Area of the shaded region =Area of square with side 10 cm - Area of circle with radius 5 cm

=  {10}^{2}  - 3.14 {(5)}^{2}  \\  = 100 - 3.14 \times 25 \\   = 100 - 78.5 \\  = 21.5 \:  {cm}^{2}

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Which are undefined terms that can be used to define other terms?
zubka84 [21]

Answer:

Point, Line, Plane

Step-by-step explanation: They are undefined terms because its is easier to define them using examples rather than word for word

5 0
3 years ago
Pls help ASAP!! 15 points?
GalinKa [24]

Answer:

4 gte g

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Plz answer!! ASAP!!
Wittaler [7]

(1) ∠ABC = 65°, ∠DBE = 65°, ∠CBE = 115°, ∠ABD = 115°

(2) ∠ABC = 62°, ∠DBE = 62°, ∠CBE = 118°, ∠ABD = 118°

Solution:

(1) In the given image ABC and DBE are vertical angles.

<u>Vertical angle theorem:</u>

If two angles are vertical then they are congruent.

⇒ ∠ABC = ∠DBE

⇒ 3x° + 38° = 5x° + 20°

Arrange like terms one side.

⇒ 38° – 20° = 5x° – 3x°

⇒ 18° = 2x°

⇒ x° = 9°

∠ABC = 3(9°) + 38° = 65°

∠DBE = 5(9°) + 20° = 65°

Adjacent angles in a straight line = 180°

⇒ ∠ABC + ∠CBE = 180°

⇒ 65° + ∠CBE = 180°

⇒ ∠CBE = 115°

∠ABD and ∠CBE are vertical angles.

∠ABD = 115°

(2) In the given image ABC and DBE are vertical angles.

⇒ ∠ABC = ∠DBE

⇒ 4x° + 2° = 5x° – 13°

Arrange like terms one side.

⇒ 13° + 2° = 5x° – 4x°

⇒ 15° = x°

∠ABC = (4(15°) + 2°) = 62°

∠DBE = 5(15°) – 13° = 62°

Adjacent angles in a straight line = 180°

⇒ ∠ABC + ∠CBE = 180°

⇒ 62° + ∠CBE = 180°

⇒ ∠CBE = 118°

∠ABD and ∠CBE are vertical angles.

∠ABD = 118°

3 0
3 years ago
What is the resistance of a 3.1 m length of copper wire 1.7 mm in diameter?
Bumek [7]
R = ?
L = 3.1 m;
r = 1.7 mm/ 2 = 0.85 mm = 0.85 * 10^(-3) m
Resistivity of copper ( rho ) = 1.68 * 10 ^(-8) [Ohm m ]
A = 3.15 * ( 0.85 * 10^(-3))^2 = 2.26865 * 10 ^(-6)
R = ( Rho ) * L / A = 1.68 * 10^(-8) * 3.1 m / 2.26865 * 10^(-6) =
= (1.7 * 3 .1 / 2.26865 )* 10^(-2) = 0.02323 Ohms ( the resistance )
8 0
4 years ago
Mr. Gephart is traveling from his house to the history museum. How many meters will he travel to the museum? The distance from h
katovenus [111]

By using relation between metre and kilometre we got that if The distance from home to the history museum is six and seven-tenths kilometres then he travel 67000 m

What is relation between metre and kilometre?

Relation between  metre and kilometre is that 1 kilometre =1000 metre

we know that kilometre and metre are two units of distance and we can convert data from one to another using their relation

Now here given distance is in kilometre

and distance is67 kilometre

We can convert 67 kilometre  in metre as

67 kilometre = 67 \times1000metre

67 kilometre = 67000 metre =67000 m

By using relation between metre and kilometre we got that if The distance from home to the history museum is six and seven-tenths kilometres then he travel 67000 m

To know more about distance visit : brainly.com/question/17273444

7 0
3 years ago
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