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bulgar [2K]
3 years ago
6

HELPPP MEEEE PLSSSS I WILL GIVE CROWN

Mathematics
1 answer:
emmasim [6.3K]3 years ago
3 0

Answer:

6

Step-by-step explanation:

if you notice here Josiah starts with 250 and Katie starts with 215, and in Josiah's equation he saves 25$ each month while Katie save 45$ each month, in order to find our answer we must multiply there starting amount by how many months.

A: 4 months is <em>incorrect</em> because Katie has 45x4+215 is 335, and Josiah has 25x4+250 is 350, so Katie is still behind

B: 5 months is <em>incorrect </em> because Katie has 45x5+215 is 375, and Josiah has, 25x5+250 which is 375, so they have the same amount of savings

C: 6 months is <em>correct</em>  because Katie has 45x6+215 is 420, and Josiah has, 25x5+250 which is 400 , so Katie has more savings, Thus C is correct

Sorry for the Wait, Your Welcome, And Have An Amazing Day

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3 years ago
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A membership committee of three is formed from four eligible members. Let the eligible members be represented by A, B, C, and D.
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The correct statement is:

  • There are four ways to choose the committee.
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It is given that:

A membership committee of three is formed from four eligible members.

1) There are four ways to choose the committee.

This statement is true.

Since we have to choose 3 members out of the 4 members so we can use the method of combination.

2) There are three ways to form the committee if person D must be on it.

This statement is also true.

Since D has to be in the committee, this means we have to choose 2 more people out of the three people to form the committee.

3) If seven members are eligible next year, then there will be fewer combinations.

This statement is wrong.

Since we have to choose 3 members out of 7 members so the number of possible combinations will be:

There are 35 combinations possible.

4) If persons B and C must be on the committee, there are two ways to form the committee.

If B and C have to be in the committee then we have to choose just one person out of the two people left.

Hence, the statement is true.

5) If persons A and C must be on the committee, then there is only one way to form the committee.

If A and C have to be on the committee then as in the last option we have to choose any one of the two-person left.

So possible number of ways is 2.

Hence, the statement is false.

Learn more about committee here: brainly.com/question/425830

#SPJ4

<em>Your question is incomplete. Please read below to find the missing content.</em>

<em />

A membership committee of three is formed from four eligible members. Let the eligible members be represented by A, B, C, and D. The possible outcomes include S = {ABC, ABD, ACD, BCD}.

Which statements about the situation are true? Check all that apply.

There are four ways to choose the committee.

There are three ways to form the committee if person D must be on it.

If seven members are eligible next year, then there will be fewer combinations.

If persons B and C must be on the committee, there are two ways to form the committee.

If persons A and C must be on the committee, then there is only one way to form the committee.

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