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hram777 [196]
2 years ago
8

A student states that the reflection of triangle ABC across the y-axis is triangle A’B’C’. Determine if the student is correct o

r has made an error. <:)

Mathematics
1 answer:
Svet_ta [14]2 years ago
8 0

Answer: The student is <u>not</u> correct

To reflect over the y axis, you use this rule

(x,y) \to (-x,y)

The x coordinate swaps in sign (from positive to negative, or vice versa) while the y coordinate stays the same.

So for a point like A(1,1), it should move to A ' (-1, 1) and not (-2,1) like the diagram shows.

B(3,1) should move to B ' (-3, 1)

C(1,4) should move to C ' (-1, 4)

It appears that the student applied a reflection over the y axis, and then they shifted the triangle 1 unit to the left.

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Answer:

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Step-by-step explanation:

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Therefore, <3 and <7 are corresponding angles.

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2 years ago
3 (x+2)+9&lt;6(x-3) solve the inequality and write the solution using interval notation​
Darya [45]

Answer:

(11, ∞).

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6 0
2 years ago
If ln(4x+y)=2x-3,then dy/dx=
Viktor [21]

\ln(4x+y)=2x-3

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\dfrac{\mathrm d(\ln(4x+y))}{\mathrm dx}=\dfrac{\mathrm d(2x-3)}{\mathrm dx}

By the chain rule, we get

\dfrac1{4x+y}\dfrac{\mathrm d(4x+y)}{\mathrm dx}=2

\dfrac{4+\frac{\mathrm dy}{\mathrm dx}}{4x+y}=2

Solve for \frac{\mathrm dy}{\mathrm dx}:

4+\dfrac{\mathrm dy}{\mathrm dx}=8x+2y

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4 0
2 years ago
True or False:
DIA [1.3K]
True. If you're just changing the form, yes. But remember when you change one side of an equation, you must change the other in the same way.
7 0
3 years ago
Read 2 more answers
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