Answer:
a.the length of midsegment of an equilateral triangle with side lengths of 12.5 cm.=12.5/2=6.25cm
b.
sinceUT is the perpendicular bisector of line segment AB, where T is on AB, find the length of AT given AT = 3x + 6 and TB = 42 - x.
than AT=BT
3x+6=42-x
3x+x=42-6
x=36/4=9
AT=3×9+6=27+6=33
c.
since angle EFG has angle bisector FH, where EF = GF, find the value of y if EH = 5y + 10 and HG = 28 - y.
EH=GH
5y+10=28-y
6y=28-10
y=18/6=3
Answer:
Step-by-step explanation:
You can't get an exact answer to this because there are no choices.
Add 9x to both sides.
3y = 9x + 12 Divide by 3
3y/3 = 9x/3 + 12/3 Combine
y = 3x + 4
Now to get anything at all that is parallel to this and providing no answer because there is no intersection of the two lines, just change the 4 to something else. Here's one example
y = 3x + 8
As long as the number in front of the x's is the same, they are parallel with no point in common.
Answer:
A' = 2,-2
B' = 2,-4
C' = 5,-4
Step-by-step explanation:
Answer:
the 0 is in the tens place.
Step-by-step explanation:
It is 8300 cause 5 is bigger than 2 so 83 and hen 00 : 83000
