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2 years ago

9

The distribution of the values of a population is shown below, and a simple Random sample is drawn from the population. Based on

this information alone, can the same will be used to make inferences about the population?

1 answer:

posledela2 years ago

6 0

Answer: C

Step-by-step explanation:

Yes, because the population values appear to be normally distributed

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6895 round to nearest thousand

garik1379 [7]

Answer:

7000

Step-by-step explanation:

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2 years ago

Please help!!! I will give brainliest but only if you try and help.

Slav-nsk [51]

Answer:

<h2>____</h2><h3>1260 </h3><h2>____</h2>

Since we have to predict, we can use ratios to help us solve this.

12 said yes out of 72 randomly chosen, SO,

if 210 would say yes (goes to play), how many is total??

12 is to 72 AS 210 is to HOW MUCH (let it be x)??

We can setup ratio, cross multiply, and solve for x:

= 12/72= 210/x

= 12x = 210*72

=12x = 15,120

=x = 15,120/12

<h2>=x =1260</h2>

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2 years ago

What is the asymptote for the graph of this logarithmic function?<br><br> f(x) = log3(x – 1)

Pepsi [2]

Answer:

Vertical Asymptote:

$x=1$

Horizontal asymptote:

it does not exist

Step-by-step explanation:

we are given

$f(x)=log_3(x-1)$

Vertical asymptote:

we know that vertical asymptotes are values of x where f(x) becomes +inf or -inf

we know that any log becomes -inf when value inside log is zero

so, we can set value inside log to zero

and then we can solve for x

$x-1=0$

we get

$x=1$

Horizontal asymptote:

we know that

horizontal asymptote is a value of y when x is +inf or -inf

For finding horizontal asymptote , we find lim x-->inf or -inf

$\lim_{x \to \infty} f(x)= \lim_{x \to \infty}log_3(x-1)$

$\lim_{x \to \infty} f(x)=log_3(\infty-1)$

$\lim_{x \to \infty} f(x)=undefined$

so, it does not exist

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3 years ago

Read 2 more answers

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Mila [183]

It is 50 thousands because 5 times 10 = 50.

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3 years ago

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miv72 [106K]

Answer:

2 books

Step-by-step explanation:

1+1=2

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3 years ago