10 pounds of sugar for 5 litres of cream.
Answer:
B) 0.894
Step-by-step explanation:
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:
![P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}](https://tex.z-dn.net/?f=P%28X%20%3D%20x%29%20%3D%20%5Cfrac%7Be%5E%7B-%5Cmu%7D%2A%5Cmu%5E%7Bx%7D%7D%7B%28x%29%21%7D)
In which
x is the number of sucesses
e = 2.71828 is the Euler number
is the mean in the given interval.
A local animal rescue organization receives an average of 0.55 rescue calls per hour.
This means that ![\mu = 0.55](https://tex.z-dn.net/?f=%5Cmu%20%3D%200.55)
Probability that during a randomly selected hour, the organization will receive fewer than two calls.
![P(X < 2) = P(X = 0) + P(X = 1)](https://tex.z-dn.net/?f=P%28X%20%3C%202%29%20%3D%20P%28X%20%3D%200%29%20%2B%20P%28X%20%3D%201%29)
In which
![P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}](https://tex.z-dn.net/?f=P%28X%20%3D%20x%29%20%3D%20%5Cfrac%7Be%5E%7B-%5Cmu%7D%2A%5Cmu%5E%7Bx%7D%7D%7B%28x%29%21%7D)
![P(X = 0) = \frac{e^{-0.55}*(0.55)^{0}}{(0)!} = 0.577](https://tex.z-dn.net/?f=P%28X%20%3D%200%29%20%3D%20%5Cfrac%7Be%5E%7B-0.55%7D%2A%280.55%29%5E%7B0%7D%7D%7B%280%29%21%7D%20%3D%200.577)
![P(X = 1) = \frac{e^{-0.55}*(0.55)^{1}}{(1)!} = 0.317](https://tex.z-dn.net/?f=P%28X%20%3D%201%29%20%3D%20%5Cfrac%7Be%5E%7B-0.55%7D%2A%280.55%29%5E%7B1%7D%7D%7B%281%29%21%7D%20%3D%200.317)
![P(X < 2) = P(X = 0) + P(X = 1) = 0.577 + 0.317 = 0.894](https://tex.z-dn.net/?f=P%28X%20%3C%202%29%20%3D%20P%28X%20%3D%200%29%20%2B%20P%28X%20%3D%201%29%20%3D%200.577%20%2B%200.317%20%3D%200.894)
Ignore the scribbles
Search up Elimination and substitution
Answer:
Step-by-step explanation:
y-(-2) = 1/2(x-12)
y+2 = 1/2x - 6
y = 1/2x -8
y = mx +b
Multiples ! By the patagrium there!!!!!