The slope of the given equation of the line, y = -3x + 2 is equal to -3. The slope of the line perpendicular to it is 1/3. The equation of the line may be expressed in slope-point form which can generally be expressed as,
y - y1 = m(x - x1)
Substituting the values,
y - 6 = (1/3)(x - 1)
Simplifying,
y = x/3 +17/3
The answer is not among the choices.
This is a freefall problem with an acceleration of -10m/s (a poor approximation of g :P)
a=g
v=gt+v0
h=gt^2/2+v0t+h0 where v0 is initial velocity and h0 is initial height.
You have:
h=-5t^2+10t+3
Since h0=3, the springboard is 3 meters above the water.
...
The diver hits the water when h=0.
5t^2-10t-3=0
Using the quadratic equation for simplicity:
t=(10±√160)/10
t=(10±4√10)/10 seconds, since t>0
t≈2.26 seconds (to nearest hundredth of a second)
So the diver hits the water about 2.26 seconds after (s)he leaves the springboard.
4374÷9=486 you could use a calculator or write down the working
