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3 years ago

Reading and Writing Decimal Numbers through Ten Thousandths

Mathematics

1 answer:

Vladimir [108]3 years ago

8 0

Answer:

1. Sixteen thousandths 2.Twenty-four Ten-thousandths 3.Eighty-four Ten-thousandths 4. Twenty-six And Thirty-seven Ten-thousandths 5.Nine And Three hundred Sixty-eight Thousandths

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00010000.00100010.10000100.10000001

Sonja [21]

Answer:

Step-by-step explanation:

What am I supposed to say?

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2 years ago

Any easy questions out there i can answer

katovenus [111]

Answer:

mee I'm in 8th

Step-by-step explanation:

plzz help will be very thankful

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4 years ago

Read 2 more answers

John is 3 years younger than twice Monica's age. If m represents Monica's age, which equation can be used to find j, John's age?

AnnZ [28]

Answer:

J =2m -3

Step-by-step explanation:

2m is twice Monica's age

-3 represents 3 years younger

7 0

3 years ago

Find a solution to the system. Make sure to write as a coordinate.

RUDIKE [14]

Answer:

x=2, y=3

Step-by-step explanation:

This is a system of equations.

To solve a system of equations, we use the substitution method.

We can plug in the first equation, $x=2y-4$ , into the value for x in the second equation. Now, the second equation looks like this:

$2*(2y-4)+y=7$

We simplify and solve for y:

→ $4y-8+y=7$

→ $5y=15$

→ $y=3$

Now, we plug in the value for y, which is 3, into either equation. I will just use the first equation:

→ $x=2*3-4$

→ $x = 2$

Let me know if my explanation is unclear.

3 0

3 years ago

Occasionally an airline will lose a bag. Suppose a small airline has found it can reasonably model the number of bags lost each

julia-pushkina [17]

Answer:

a) The probability that the airline will lose no bags next monday is 0.1108

b) The probability that the airline will lose 0,1, or 2 bags next Monday is 0.6227

c) I would recommend taking a Poisson model with mean 4.4 instead of a Poisson model with mean 2.2

Step-by-step explanation:

The probability mass function of X, for which we denote the amount of bags lost next monday is given by this formula

$P(X=k) = \frac{e^{-2.2} * {2.2}^k }{k!}$

$P(X=0) = \frac{e^{-2.2} * {2.2}^0 }{0!} = 0.1108$

The probability that the airline will lose no bags next monday is 0.1108.

b) Note that $P(X \in \{0,1,2\} = P(X=0) + P(X=1) + P(X=2)$ . And

$P(X=0)+P(X=1)+P(X=2) = e^{-2.2} * (1 + 2.2 + 2.2^2/2) = 0.6227$

Therefore, the probability that the airline will lose 0,1, or 2 bags next Monday is 0.6227.

c) If the double of flights are taken, then you at least should expect to loose a similar proportion in bags, because you will have more chances for a bag to be lost. WIth this in mind, we can correctly think that the average amount of bags that will be lost each day will double. Thus, i would double the mean of the Poisson model, in other words, i would take a Poisson model with mean 4.4, instead of 2.2.

6 0

3 years ago