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Juli2301 [7.4K]
3 years ago
10

The number of children studying in different schools of kanpur is 6,45,55,587 . If the number of boys is 4,55,25,400, find the n

umber of girls.
Mathematics
1 answer:
KiRa [710]3 years ago
3 0

Answer:

19030187 girls

Step-by-step explanation:

Total number of children = 6,45,55,587

number of boys =4,55,25,400

Number of girls= (Total number of children ) - (number of boys )

= (6,45,55,587)-(4,55,25,400)

= 19030187 girls

The number of girls. Is 19030187

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horsena [70]

Answer: 8 hours

Step-by-step explanation: You would first multiply 2 hours by 4 mph, and get 8 miles. You would then subtract 8 miles from 26 miles, and have 18 miles left. You would now divide 18 miles by 3, as he is now traveling 3 miles per hour and needs to travel 18 miles. You would get 6 hours. You would now add 6 hours by the 2 hours initially traveled at 4 mph, and get 8 hours.

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2 years ago
Mean for 16, 12, 13, 22
pishuonlain [190]

Answer:

mean = sum of the terms/total no. of terms

mean = (16+12+13+22)/4

mean = 63/4 or 15.75

6 0
3 years ago
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adoni [48]

why do u cheat in exams lol

5 0
3 years ago
Find the solution of the given initial value problem:<br><br> y''- y = 0, y(0) = 2, y'(0) = -1/2
igor_vitrenko [27]

Answer:  The required solution of the given IVP is

y(x)=\dfrac{3}{4}e^x+\dfrac{5}{4}e^{-x}.

Step-by-step explanation:  We are given to find the solution of the following initial value problem :

y^{\prime\prime}-y=0,~~~y(0)=2,~~y^\prime(0)=-\dfrac{1}{2}.

Let y=e^{mx} be an auxiliary solution of the given differential equation.

Then, we have

y^\prime=me^{mx},~~~~~y^{\prime\prime}=m^2e^{mx}.

Substituting these values in the given differential equation, we have

m^2e^{mx}-e^{mx}=0\\\\\Rightarrow (m^2-1)e^{mx}=0\\\\\Rightarrow m^2-1=0~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mx}\neq0]\\\\\Rightarrow m^2=1\\\\\Rightarrow m=\pm1.

So, the general solution of the given equation is

y(x)=Ae^x+Be^{-x}, where A and B are constants.

This gives, after differentiating with respect to x that

y^\prime(x)=Ae^x-Be^{-x}.

The given conditions implies that

y(0)=2\\\\\Rightarrow A+B=2~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

and

y^\prime(0)=-\dfrac{1}{2}\\\\\\\Rightarrow A-B=-\dfrac{1}{2}~~~~~~~~~~~~~~~~~~~~~~~~(ii)

Adding equations (i) and (ii), we get

2A=2-\dfrac{1}{2}\\\\\\\Rightarrow 2A=\dfrac{3}{2}\\\\\\\Rightarrow A=\dfrac{3}{4}.

From equation (i), we get

\dfrac{3}{4}+B=2\\\\\\\Rightarrow B=2-\dfrac{3}{4}\\\\\\\Rightarrow B=\dfrac{5}{4}.

Substituting the values of A and B in the general solution, we get

y(x)=\dfrac{3}{4}e^x+\dfrac{5}{4}e^{-x}.

Thus, the required solution of the given IVP is

y(x)=\dfrac{3}{4}e^x+\dfrac{5}{4}e^{-x}.

4 0
3 years ago
There are 2 Senators from each of 50 states. We wish to make a 3-Senator committee in which no two members are from the same sta
Morgarella [4.7K]

Answer:

a) rCn = 1176

b) 2352

Step-by-step explanation:

a)Each committee should be formed with 3 members ( no two members could be of the same state) then

Let´s  fix a senator for any of the 50 states so in the new condition we need to combined 49 senators in groups of 2 then

rCn =  n! / (n - r )! *r!

rCn =  49!/ (49 - 2)!*2!

rCn =  49*48*47! / 47!*2!

rCn = 49*48 /2

rCn = 1176

So we can choose in 1176 different ways a senator for a given state

b) To answer this question we have to note, that, 1176 is the number of ways a committee can be formed with senators of different sate (taking just one senator for state ) if we have 2 senators we need to multiply that figure by 2.

1176*2 = 2352

6 0
3 years ago
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