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3 years ago

Can yall pls help with this

Mathematics

1 answer:

Blizzard [7]3 years ago

3 0

Answer:

x=7

Step-by-step explanation:

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Find the distance between the following points<br> C(11, -12), D(6, 2)

Lady bird [3.3K]

Answer:

14.9

Step-by-step explanation:

Formula= $\sqrt{(x2-x1)^{2} +(y2-y1)^{2}$

x1=11; y1=-12; x2=6; y2=2

Putting these values in the formula, the result will be 14.866≡14.9

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3 years ago

If an object is projected upward from the top of a 144 ft building at 112 ft per sec, its position (in feet above the ground) is

Mandarinka [93]

When it hits the ground the height would be 0.

Set h to 0 and solve for t ( time)

0 = -16t^2 + 112t + 144 divide both sides by -16:

T^2 -7t -9

Factor the polynomial :

( t- 8.1) (t+1.1

Solve for t setting each equation to 0:

T = 8.1 or t = -1.1

Time has to be positive, so the answer is

8.1 seconds

Depending on how everything gets rounded it could also be 8 seconds.

8 0

4 years ago

The volume of a cylinder is the base (B) times the length of its height (h).

levacccp [35]

Answer:

$\text{The formula of a volume of a cylinder:}\\\\V=BH\\\\B-base\ area\\H-height\\\\\large\huge\boxed{\bold{B.\ V=Bh}}$

5 0

3 years ago

Read 2 more answers

How many $1 dollar bills do i need to circle the earth? Thanks

ozzi

1 billion dollars × 6 inches per dollar = 6 billion inches / 63,360 inches per mile = 94,636.97 miles coverted by1 billion bills. answer = 94,636.97 miles

8 0

4 years ago

In the game of roulette, a player can place a $4 bet on the number 29 and have a 1/38 probability of winning. If the metal bal

creativ13 [48]

Answer:

The expected value of the game to the player is -$0.2105 and the expected loss if played the game 1000 times is -$210.5.

Step-by-step explanation:

Consider the provided information.

It is given that if ball lands on 29 players will get $140 otherwise casino will takes $4.

The probability of winning is 1/38. So, the probability of loss is 37/38.

Now, find the expected value of the game to the player as shown:

$E(x)=(140)\times \frac{1}{38}+(-4)\times \frac{37}{38}$

$E(x)=\frac{140-148}{38}$

$E(x)=\frac{-8}{38}=-$0.2105$

Hence, the expected value of the game to the player is -$0.2105.

Now find the expect to loss if played the game 1000 times.

1000×(-$0.2105)=-$210.5

Therefore, the expected loss if played the game 1000 times is -$210.5.

5 0

3 years ago