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2 years ago

1

Mathematics

1 answer:

Vadim26 [7]2 years ago

6 0

Answer:

x+2

Step-by-step explanation:

The firs 3 observations are x, x+2, x+4

Mean = sum of data/samaple size

Mean = x+x+2+x+4/3

MEan = 3x+6/3

Mean = 3(x+2)/3

Mean = x+2

Hence the required mean is x+2

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Volume (to the nearest tenth)

Ivenika [448]

Answer:

913

Step-by-step explanation:

cylinder:

radius=5.6 height=7

first lets find the volume of the cylinder the formula for the volume of a cylinder is pi times radius squared times height. so after plugging in the height and radius you get 689.64242

cone:

radius=5.6 height=6.8

now the volume of the cone, the formula for the volume of a cone is pi times radius squared times height/3. so after plugging in the height and radius of the cone you get 223.31278

so 689.64242 + 223.31278= 912.9552 and that rounded to the nearest tenth is 913

3 0

1 year ago

a. It is important to label all your variables and expressions clearly because: it will help you get your equations set up c. it

sveticcg [70]

Answer:

I'm pretty sure it's A. It will help you get your equations set up correctly

Step-by-step explanation:

For anyone needing this answer in the future lol

3 0

2 years ago

Please Help - Point x^3-4x<-5x^2+20 Solve in interval notation and list the zeros

Naddika [18.5K]

hi my name is antonette Jane S pascua please help me my question thank you for your answer

4 0

2 years ago

Solve the inequality state your answer algebraicly and in interval notation 4(n-3)-2n<-10+2n

AlexFokin [52]

Answer:

See below

Step-by-step explanation:

Expand L side to get

4n -12 -2n < -10 + 2n simplify L side

2n -12 < -10 +2n subtract 2n from both sides

-12 < -10 <===== so the equation is true for ALL n

(-∞ , + ∞ )

4 0

1 year ago

What is the solution to the equation below?

hram777 [196]

Answer:

$\large\boxed{A)\ x=-4}$

Step-by-step explanation:

$\dfrac{x}{4}=\dfrac{x+1}{3}\qquad\text{cross multiply}\\\\3x=4(x+1)\qquad\text{use the distributive property}\\\\3x=4x+4\qquad\text{subtract}\ 4x\ \text{from both sides}\\\\-x=4\qquad\text{change the signs}\\\\x=-4$

4 0

2 years ago