There are 52 cards in a standard deck so that would be the whole in the part/whole equation so
i... There are 13 spade cards and then 3 other aces since there are 4 suits of cards so 16/52 or about 0.30769 or 30.8% rounded
ii....There are 2 reds of each card in a standard deck along with 2 blacks so there would be 2 red kings which would be a 2/52 chance or about 0.0384 or 3.8% rounded
iii.... There are 4 kings and 4 queens in each deck so (52-8)/52 which is a 44/52 chance, 0.8461 about, or 84.6% rounded
iv..., As I said in iii, there are 8 kings and queens so an 8/52 chance, about 0.1538, or 15.4% rounded
Answer:
5
Step-by-step explanation:
none of the above are true
1. intersect at x=45
so y=sqrt(2)
2. y=cscx period is doubled y=tanx
3. not the same
4. no local maximum of y=secx
minimum point of y=sinx is -1
so none of the above are true
Answer:
3 3/10
Step-by-step explanation:
In order to do this, you need to find the least common multiple. When you do that, you get 5/10 and 2 8/10. Next, what you what to do is turn 2 and 8/10 to an improper fraction, and when you do that you get 28/10. Add 28/10 and 5/10 to get 33/10. Simplify 33/10, and the correct answer is 3 3/10.
Answer:
z(max) = 256000 Php
x₁ = 10
x₂ = 110
Step-by-step explanation:
Jogging pants design Selling Price Cost
weekly production
Design A x₁ 2500 1750
Design B x₂ 2100 1200
1. z ( function is : )
z = 2500*x₁ + 2100*x₂ to maximize
First constraint weekly production
x₁ + x₂ ≤ 120
Second constraint Budget
1750*x₁ + 1200*x₂ ≤ 150000
Then the model is
z = 2500*x₁ + 2100*x₂ to maximize
Subject to
x₁ + x₂ ≤ 120
1750*x₁ + 1200*x₂ ≤ 150000
General constraints x₁ ≥ 0 x₂ ≥ 0 both integers
First table
z x₁ x₂ s₁ s₂ cte
1 -2500 -2100 0 0 0
0 1 1 1 0 = 120
0 1750 1200 0 1 = 150000
Using AtoZmath online solver and after 6 iterations the solution is:
z(max) = 256000 Php
x₁ = 10
x₂ = 110
