Question

Write a recursive method named digitSum that accepts an integer as a parameter and returns the sum of its digits. For example, calling digitSum(1729) should return 1 7 2 9, which is 19. If the number is negative, return the negation of the value. For example, calling digitSum(-1729) should return -19.

Answer 1

Answer:

The function in Python is as follows:

def digitSum( n ):

if n == 0:

 return 0

if n>0:

    return (n % 10 + digitSum(int(n / 10)))

else:

    return -1 * (abs(n) % 10 + digitSum(int(abs(n) / 10)))

Explanation:

This defines the method

def digitSum( n ):

This returns 0 if the number is 0

if n == 0:

 return 0

If the number is greater than 0, this recursively sum up the digits

if n>0:

    return (n % 10 + digitSum(int(n / 10)))

If the number is lesser than 0, this recursively sum up the absolute value of the digits (i.e. the positive equivalent). The result is then negated

else:

    return -1 * (abs(n) % 10 + digitSum(int(abs(n) / 10)))