Question

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In the given figure , AP = BP = PC. Prove that $\angle$ABC = 1 rt.angle.

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Answer 1

Answer:

See Below.

Step-by-step explanation:

In the given figure, AP = BP = PC.

And we want to prove that ∠ABC is a right angle.

Since AP = BP and BP = PC, we can create two isosceles triangles: ΔAPB and ΔCPB.

By the definition of isosceles triangles, in ΔAPB, ∠PAB and ∠PBA are equivalent. Let the measure of each of them be x°.

Likewise, in ΔCPB, ∠PCB and ∠PBC are equivalent.

And since AP = BP = PC, each of the angles∠PCB and ∠PBC will also be equivalent to x°.

And since the sum of the interior angles of a triangle total 180°, we acquire:

$\angle PAB+\angle PBA+\angle PCB+\angle PBC=180$

Since they are all equivalent:

$4x=180$

Hence:

$x=45^\circ$

∠ABC is the sum of ∠PBA and ∠PBC, each of which measures 45°. Hence:

$\angle ABC=\angle PBA+\angle PBC=45+45=90^\circ$

Answer 2

Answer:

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