First subtract manny value 36.5 from Evan values 18 which will give u 18.5 cm which then u have to convert. Since 1 cm is about .4, we can multiply 18.5 by .4 to get the answer 7.4 inches
A) I included a graph, look below.
B)
Input the y in x = y + 3.
x = (-4x - 3) + 3
x = -4x + 0
Add 4x to both sides.
5x = 0
Divide both sides by 5.
x = 0
Input that x value in y = -4x - 3
y = -4(0) - 3
y = 0 - 3
y = -3
(0, -3)
C)
Convert both equations to Standard Form.
x = y + 3
Subtract y from both sides.
x - y = 3
y = -4x - 3
Add 4x to both sides.
4x + y = -3
Add the equations together.
4x + y = -3
x - y = 3
equals
5x = 0
Divide both sides by 5.
x = 0
Input that into one of the original equations.
0 = y + 3
Subtract 3 from both sides.
-3 = y
(0, -3)
The seedling grew 1 1/6 inches or approximately 1.16 inches. 1/3 is equal to 2/6, 2/6 + 5/6 = 7/6
7/6 = 1 1/6
Answer: See explanation
Step-by-step explanation:
3.) Boys║5║<em>10 ║</em>60
Girls ║7║ 14 ║<em>84</em>
7 × 2 = 14
5 × 2 = 10
5 × 12 = 60
7 × 12 = 84
Hope I helped!
Answer:

Step-by-step explanation:
We are given that

We have to find the implicit function
Using separation variable method

By using property 

By using property 
Taking integration on both sides

Parts integration method

By parts integration method

Using formula 



We are given that

