Solve the equation. −10=−b4

Mathematics

2 answers:

Fantom [35]2 years ago

5 0

Answer:

b = 1.778279, −1.778279

Step-by-step explanation:

vitfil [10]2 years ago

3 0

-10=b4 <----- Write your equation out

-10= $\frac{b4}{4}$ <----- Divide b4 by 4 to get b by itself.

$\frac{-10}{4}$ =b <----- Divide -10 by 4 because what you do to one side, you mjst do to the other.

-2.5=b <----- There is your answer; -2.5

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The weight of Jane and Jessica was in the ratio of 8 : 9. Jane gained 2 kg while Jessica lost 4 kg. They then had the same weigh

postnew [5]

Answer:

48 kg

Step-by-step explanation:

The given relations can be used to write a system of equations for the two weights. Those can be solved to find Jane's weight.

<h3>setup</h3>

Let x and y represent Jane's and Jessica's original weight, respectively. The ratio of weights was ...

x/y = 8/9

After the changes in weight, they were equal:

x+2 = y-4

<h3>solution</h3>

Adding 4 to the second equation, we have an expression for y that can be substituted into the first equation.

y = x +6 . . . . . . . . . . solve the second equation for y

x/(x+6) = 8/9 . . . . . . substitute for y in the first equation

9x = 8(x +6) . . . . . . . multiply by 9(x+6)

x = 48 . . . . . . . . . . . simplify and subtract 8x

Jane weighed 48 kg at first.

_____

<em>Alternate solution</em>

The original difference in "ratio units" was 9-8 = 1 ratio unit. We find that this corresponds to 6 kg after the weight changes make the weights equal. Then 8 ratio units will be 8(6 kg) = 48 kg—Jane's original weight.

(This mental solution is virtually the same as the solution using equations shown above.)